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jeyben [28]
3 years ago
5

What is the 4th term in the sequence b(n)=1(-2)^n-1

Mathematics
1 answer:
mel-nik [20]3 years ago
8 0
b(n)=1(-2)^n-1

When n = 4, 
b(4)=1(-2)^4-1

b(4)=16-1

b(4)=15

-------------------------------------------------------------

b(n)=1(-2)^{n-1}

When n = 4
b(4)=1(-2)^{4-1}

b(4)=1(-2)^3

b(4)=1(-8)

b(4)=-8

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