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3 years ago

Solve The Question On Photo

Mathematics

1 answer:

bezimeni [28]3 years ago

5 0

Answer: The answer that i got is h ≤ 5

Step-by-step explanation:

First , convert mixed numbers to improper fractions : 5 3/4 to 23/4.
Then, convert 9 1/4 to improper fraction : to 37/4
After, Add 23/4 to both of the sides.
Like this, - 23/4 + 3h + 23/4 ≤ 37/4 + 23/4
Then simplify 3h ≤ 15
Finally your answer will be h ≤ 5

* Hopefully this helps:) Mark me the brainliest:)!!!

<em>∞ 234483279c20∞</em>

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PLEASE HELP!!

Katena32 [7]

The formula for a regular polygon, which this one is, is A = 1/2 ap where a is the apothem and p is the perimeter. 20.8 * 7 = 145.6 which is the perimeter, so now just multiply by 21.6 and .5. 145.6 * 21.6 * .5 = 1572.48, or B above.

3 0

3 years ago

Please help! i have no clue if it's equivalent :(

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

y+2=y+2

Step 2: Subtract y from both sides.

y+2−y=y+2−y

2=2

Step 3: Subtract 2 from both sides.

2−2=2−2

0=0

Answer:

All real numbers are solutions.

4 0

3 years ago

Read 2 more answers

An experiment has a high degree of ______________ when it shows convincingly that changes in behavior are a function of the inde

adelina 88 [10]

The answer is Internal Validity.

Internal Validity is high in an experiment. when it demonstrates persuasively that changes in behavior are caused by the independent variable and not by unknown factors.

What is Internal Validity?

Internal validity is defined as the degree to which the observed results represent the truth in the population under investigation and are not the consequence of methodological flaws.
Internal validity is the degree of certainty that the causal link being examined is reliable and unaffected by other factors or variables.
The extent to which study results may be extended (generalized) to other contexts, groups, or events is referred to as external validity.

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1 year ago

Joe has a bag of 24 pieces of candy. He gives 1/8 of them to a friend,

kobusy [5.1K]

Answer:

18 pieces.

Step-by-step explanation:

1/8 of 24 is 3.

24 - 3 = 21, that's how much he has left after giving it to the first friend.

1/7 of 21 is also 3.

21 - 3 = 18, there's your answer.

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3 years ago

Read 2 more answers

Find the center of mass of the wire that lies along the curve r and has density =4(1 sin4tcos4t)

dolphi86 [110]

The mass of the wire is found to be 40π√2 units.

To calculate the mass of the wire which runs along the curve r ( t ) with the density function δ=5.

The general formula is,

Mass = $\int_a^b \delta\left|r^{\prime}(t)\right| d t$

To find, we must differentiate this same given curve r ( t ) with respect to t to estimate |r'(t)|.

The given integration limits in this case are a = 0, b = 2π.

Now, as per the question;

The equation of the curve is given as;

r(t) = (4cost)i + (4sint)j + 4tk

Now, differentiate this same given curve r ( t ) with respect to t.

$\begin{aligned}\left|r^{\prime}(t)\right| &=\sqrt{(-4 \sin t)^2+(4 \cos t)^2+4^2} \\&=\sqrt{16 \sin ^2 t+16 \cos ^2 t+16} \\&=\sqrt{16\left(\sin t^2+\cos ^2 t\right)+16}\end{aligned}$

Further simplifying;

$\begin{aligned}&=\sqrt{16(1)+16} \\&=\sqrt{16+16} \\&=\sqrt{32} \\\left|r^{\prime}(t)\right| &=4 \sqrt{2}\end{aligned}$

Now, use integration to find the mass of the wire;

$\begin{aligned}&=\int_a^b \delta\left|r^{\prime}(t)\right| d t \\&=\int_0^{2 \pi} 54 \sqrt{2} d t \\&=20 \sqrt{2} \int_0^{2 \pi} d t \\&=20 \sqrt{2}[t]_0^{2 \pi} \\&=20 \sqrt{2}[2 \pi-0] \\&=40 \pi \sqrt{2}\end{aligned}$

Therefore, the mass of the wire is estimated as 40π√2 units.

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The complete question is-

Find the mass of the wire that lies along the curve r and has density δ.

r(t) = (4cost)i + (4sint)j + 4tk, 0≤t≤2π; δ=5

5 0

2 years ago

Solve The Question On Photo​

Solve The Question On Photo