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3 years ago

What is the equation of the line through (4,5) and (0,-3)

Mathematics

2 answers:

Allisa [31]3 years ago

8 0

Answer:

y = 2x - 3

Step-by-step explanation:

Slope intercept equation of a line:

y = mx + b

(0, -3) is the y-intercept, so b = -3

We have

y = mx - 3

Now we use the two points to find the slope.

slope = m = (-3 - 5)/(0 - 4) = -8/(-4) = 2

y = 2x - 3

luda_lava [24]3 years ago

4 0

Answer:

4,5x+-3

Step-by-step explanation:

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2 years ago

5x - x = -12 what is x???

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X would equal -3. 5x-3 would equal -15, and 2 negatives would equal a positive. So, -15+3 would equal -12.

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3 years ago

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Please help and explain if so thank you

myrzilka [38]

Answer:

Step-by-step explanation:

Slope-intercept form:

y = mx + b

m = slope; b = y-intercept

A line with slope 0 is a horizontal line. Since one point on the line has y-coordinate 6, then all points on the line have y-coordinate 6. The y-intercept is 6.

m = 0; b = 6

y = mx + b

y = 0x + 6

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4 0

3 years ago

A research study uses 800 men under the age of 55. Suppose that 30% carry a marker on the male chromosome that indicates an incr

ss7ja [257]

Answer:

a) There is a 12.11% probability that exactly 1 man has the marker.

b) There is a 85.07% probability that more than 1 has the marker.

Step-by-step explanation:

There are only two possible outcomes: Either the men has the chromosome, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

30% carry a marker on the male chromosome that indicates an increased risk for high blood pressure, so $\pi = 0.30$

(a) If 10 men are selected randomly and tested for the marker, what is the probability that exactly 1 man has the marker?

10 men, so $n = 10$

We want to find P(X = 1). So:

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{10,1}.(0.30)^{1}.(0.7)^{9} = 0.1211$

There is a 12.11% probability that exactly 1 man has the marker.

(b) If 10 men are selected randomly and tested for the marker, what is the probability that more than 1 has the marker?

That is $P(X > 1)$

We have that:

$P(X \leq 1) + P(X > 1) = 1$

$P(X > 1) = 1 - P(X \leq 1)$

We also have that:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{10,0}.(0.30)^{0}.(0.7)^{10} = 0.0282$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0282 + 0.1211 = 0.1493$

Finally

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1493 = 0.8507$

There is a 85.07% probability that more than 1 has the marker.

3 0

3 years ago