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alekssr [168]
3 years ago
12

0.00456 scientific notation

Mathematics
1 answer:
taurus [48]3 years ago
3 0

Answer:

4.56 × 10^ − 3

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the  10 . If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

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Solve the equation. Check your solutions when necessary.<br><br><br>2x² − 7x = 4
prisoha [69]

Answer:

x= -1/2 = -0.500

x=4

Step-by-step explanation:

2x^2-7x-4=0

2x^2-8x+1x-4=0

2x(x-4)+1(x-4)=0

(2x+1)(x-4)=0

2x+1=0...2x= -1.. x= -1/2         x-4=0 .. x=4

checking the solution

2(-1/2)^2-7(-1/2)=4.....  4=4

2(4)^2-7(4)=4....... 4=4

5 0
3 years ago
Arlene had 1/3 as many goldfish as Isabelle. Isabelle has 5 times as many goldfish as Bruce. If Bruce had 18 goldfish, how many
kvv77 [185]

Answer: 30 goldfish

Step-by-step explanation: Bruce has 18 goldfish. If Isabelle has 5 times as many goldfish as Bruce she will have 18*5=90 goldfish. If Arlene has 1/3 times as many goldfish as Isabelle she will have 90/3=30 goldfish.

7 0
3 years ago
WILL GIVE BEST RESPONSE
tino4ka555 [31]
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1, 
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
<span>
</span>
4 0
3 years ago
Which angles shown in the drawing are supplementary
Arte-miy333 [17]
In order to answer this, we need an image to be able to see what they look like.
5 0
3 years ago
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
3 years ago
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