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4 years ago

Paul worked 5 hours as a painter and

Mathematics

2 answers:

MAVERICK [17]4 years ago

7 0

Answer:

$85.20

Step-by-step explanation:

53.25/5=10.65

Y=10.65x

Y=10.65(8)

Y=85.2

kogti [31]4 years ago

5 0

Answer:

85.2

Step-by-step explanation:

first divide 53.25 by 5 to get the per hour amount.

Then times that number by 8.

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86 divide by 3 using area model,

IgorLugansk [536]

Answer:

86/3=28.67

Step-by-step explanation:

5 0

3 years ago

Which measurement is greatest? 6 kilometers, 60 meters,600 centimeters, 6000 millimeters

Rashid [163]

Convert all of them to meters.

1 km = 1000 meters

6 * 1000 = 6000

6 km = 6000 m

1 cm = 0.01 m

600 * 0.01 = 6

600 cm = 6 m

1 mm = 0.001 m

6000 * 0.001 = 6 m

So we have:

6000 m, 60 m, 6 m, and 6 m.

So 6 kilometers is the greatest.

8 0

4 years ago

Read 2 more answers

G = -7 and h = 3 What is the answer for g+h=

andrew11 [14]

Simply plug g and h into the equation:

g + h =

(-7) + (3) = -4

8 0

4 years ago

Read 2 more answers

Write an equation of the line in slope-

SashulF [63]

Answer:

Step-by-step explanation:

y= -5/2x-1

3 0

3 years ago

Read 2 more answers

A planet follows an elliptical path described by 16 x squared + 4 y squared = 64. A comet follows the parabolic path y equals x

saul85 [17]

Answer:

The comet might intersect the orbiting planet at (0, -4), $(\pm\frac{\sqrt{31}}{2},\frac{15}{4})$ .

Step-by-step explanation:

Given that, a planet follows an elliptical path described by

$16x^2+4y^2=64$ .........(1)

A comet follows the parabolic path

$y=x^2-4$

$x^2=y+4$ .........(2)

To find the intersecting point, we need to solve the above equations.

Putting $x^2=y+4$ in the equation (1)

$y+4+4y^2=64$

$\Rightarrow 4y^2+y+4-64=0$

$\Rightarrow 4y^2+y-60=0$

$\Rightarrow 4y^2+16y-15y-60=0$

$\Rightarrow 4y(y+4)-15(y+4)=0$

$\Rightarrow(y+4)(4y-15)=0$

$\Rightarrow y=-4, \frac{15}{4}$

When y = -4 , then $x^2=-4+4$ $\Rightarrow x=0$

When $y=\frac{15}{4}$ , then $x^2=\frac{15}{4}+4$ $\Rightarrow x=\pm \frac{\sqrt{31}}{2}$

The comet might intersect the orbiting planet at (0, -4), $(\pm\frac{\sqrt{31}}{2},\frac{15}{4})$ .

5 0

3 years ago