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slamgirl [31]
3 years ago
14

What is the solution set?

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0

\left \{ {{y=x^2+2x+7} \atop {y=x+7}} \right. \left \{ {{x+7=x^2+2x+7} \atop {y=x+7}} \right. \left \{ {{x^2+2x-x+7-7=0} \atop {y=x+7}} \right. \left \{ {{x^2+x=0} \atop {y=x+7}} \right. \\\left \{ {{x(x+1)=0} \atop {y=x+7}} \right. \left \{ {{x_1=0, x_2=-1} \atop {y_1=0+7},y_2=-1+7} \right. \left \{ {{x_1=0, x_2=-1} \atop {y_1=7},y_2=6} \right.

There are 2 solution sets: (0,7) and (-1;6).

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Graph the funtion f(x) - -3x + 6
scoundrel [369]

Answer:

The y intercept is 6 and the slope is -3.

Please see the attached graph.

6 0
4 years ago
Ebi, Jose, Derell, and Asami measured their heights. Ebi's height was 2.5 cm greater than Jose's height. Jose's height was 3.1 c
irga5000 [103]
Start with assigning each person with a variable to represent their height

Ebi: e
Jose: j
Derell: d
Asami: a

Ebi'd height was 2.5 cm greater than Jose's height

j + 2.5 = e

Jose's height was 3.1 cm greater than Derell's

d + 3.1 = j

Derell's height is 0.4 cm less than Asami's height

a - 0.4 = d

Ebi is 162.5 cm tall

e = 162.5

So, plug in 162.5 into any of the above equations were there is a variable of e

j + 2.5 = e

j + 2.5 = 162.5

Subtract 2.5 from both sides of the equation

j = 160 cm

Jose's height is 160 cm

Now, plug in 160 into any of the above equations where there is a j

d + 3.1 = j

d + 3.1 = 160

Subtract 3.1 from both sides of the equation 

d = 156.9 cm

Derell's height 156.9 cm

so, plug in 156.9 into any of the above equations where there is a d

a - 0.4 = d

a - 0.4 = 156.9

Add 0.4 on both sides of the equation

a = 157.3 cm

Asami's height is 157.3 cm



7 0
3 years ago
Read 2 more answers
A garden measuring 16 meters by 8 meters is going to have a walkway constructed all around the perimeter, increasing the total a
Semenov [28]

Answer:

The width of the pathway is:

  • <u>7 meters</u>.

Step-by-step explanation:

To identify the width of the pathway, you must remember the area formula of a rectangle:

  • Area of a rectangle = length * width.

From which the width can be cleared:

  • Width of a rectangle = area / length.

We know that the length of the terrain was not modified since the pathway is in the perimeter of the rectangle (16 m) and that the new area is 240 m^2, so we only have to replace the cleared formula:

  • Width of a rectangle = 240 m^2 / 16 m = 15 m.

The new width is equal to 15 meters, but since the question is not the total width but the width of the pathway, the width of the previously provided land must be subtracted from the value obtained.

  • <u>Pathway width = Total width - Garden width. </u>
  • <u>Pathway width = 15m - 8m = 7 meters.</u>
7 0
3 years ago
future value of 10% savings from earnings of 36000 earns 6.25% annual interest compounded quarterly for 15 years​
hoa [83]

without further ado

10% of 36000 is simply 3600, we chopped a "0" off of it hmmm, ok so

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3600\\ r=rate\to 6.25\%\to \frac{6.25}{100}\dotfill &0.0625\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &15 \end{cases} \\\\\\ A=3600\left(1+\frac{0.0625}{4}\right)^{4\cdot 15}\implies A=3600(1.015625)^{60}\implies A\approx 9126.53

7 0
3 years ago
What statement is true about the graphs of the two lines y = -6 and x = 1/6?
pav-90 [236]

the two lines are perpendicular

y = -6 is a horizontal line  ( slope of  0) and x = 1/6 is a vertical line  (undefined slope).  These are perpendicular to each other

4 0
3 years ago
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