If n is an integer, then cos(n(2<span>π))=1.
Take n=0, cos(2</span>π)=cos(0)=1, n=1, cos(2π)=1, n=2, cos(2(2π))=cos(4<span>π)=cos(0)=1...
If n is not an integer, well, ..... we don't know the value, which depends on the value of n.</span>
There is something wrong with drawing. IC intercepts with AB at A.
Answer:
Step-by-step explanation:
The graph passes through the origin. It could either open up or open down. The quadratic has two zeros, both at (0, 0).
Answer:
not enough info
Step-by-step explanation:
not enough info
