Evaluate 10m + when m = 5 and n = 4.

Simplify -3-20 divided by (-2*1) Is the answer 7?

Anna35 [415]

No the answer is -13. Please mark me brainliest!

8 0

3 years ago

The line with equation a + 2b = 0 coincides qith the terminal side of an angle theta in standard position and cos theta < 0.

lana [24]

Nhbgyhjbhuknhggyubccfjmcd

3 0

3 years ago

A sample of eight workers in a clothing manufacturing company gave the following figures for the amount of time(in minutes) need

lilavasa [31]

Answer:

$10.108 < \mu < 13.892$

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

We have the following distribution for the random variable:

$X \sim N(\mu , \sigma=0.45)$

And by the central theorem we know that the distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=12$

The sample deviation calculated $s=2.268$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=8-1=7$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,7)".And we see that $t_{\alpha/2}=2.36$

Now we have everything in order to replace into formula (1):

$12-2.36\frac{2.268}{\sqrt{8}}=10.108$

$12+2.36\frac{2.268}{\sqrt{8}}=13.892$

So on this case the 95% confidence interval would be given by (10.108;13.892)

$10.108 < \mu < 13.892$

7 0

3 years ago

Using the equation representing the height of the firework (h = -16t2 + v0t + h0), algebraically determine the extreme value of

lubasha [3.4K]

-16t^2 + v0t + h0

= -16(t^2 - 1/16 v0t) + h0
= -16 [(t - 1/32v0)^2 - (1/32 v0)^2 ) + h0
= -16(t - 1/32v0)^2 + 1/64 (v0)^2 + h0 which is the vertex form

The vertex is at the point (1/32v0, 1/64 (v0)^2)

1/32v0 represents the time when the firework is at its maximum height and 1/64 (v0)^2 is this maximum height

6 0

3 years ago

Read 2 more answers

MArsha joged 7.8 miles. Erica jogged 0.5 tyimes as far . HOw far did erica jogged

tangare [24]

you would do 7.8 times 0.5 and would get 3.9. You would add 7.8 and 3.9 and get 11.7 That is your answer

3 0

3 years ago