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Misha Larkins [42]
3 years ago
14

A custom rectangular tabletop has a length that is twice it’s width, and the tabletop measures 76 inches on its diagonal. What a

re the dimensions of the tabletop? What is it’s perimeter?
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
5 0

Answer:

<em>The dimensions of the tabletop: Length= 67.976... inches and Width= 33.988... inches and the perimeter will be 203.929... inches.</em>

Step-by-step explanation:

Suppose, the width of the rectangular tabletop is x inch.

As the tabletop has a length that is twice it’s width, so the length will be:  2x inch.

The tabletop measures 76 inches on its diagonal.

<u>Formula for length of diagonal of rectangle</u>:  d=\sqrt{l^2+w^2}

So, the equation will be..........

76=\sqrt{(2x)^2+ x^2}\\ \\ 76=\sqrt{4x^2+x^2} \\ \\ 76=\sqrt{5x^2} \\ \\ 5x^2= 76^2= 5776\\ \\ x^2= \frac{5776}{5}=1155.2 \\ \\ x= \sqrt{1155.2} =33.988...

Thus, the width of the tabletop is 33.988... inches and the length will be:  (2×33.988...) = 67.976... inches.

The perimeter will be:  2(33.988...+ 67.976...) inches = 203.929... inches.

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2. Ashley had a summer lemonade stand where she sold small cups of lemonade for $1.25 and large
Drupady [299]

Answer:

\boxed {\boxed {\sf 98 \ Small \ Cups}}\\\\\boxed {\boxed {\sf 57 \ Large \ Cups}}

Step-by-step explanation:

Let's make a system of equations.

First, define the variables.

Let s= small cups and g= large cups

Next, make 2 equations. 1 for the money and 1 for the number of cups.

<u>Money</u>

  • A small cup costs 1.25 and a large cup costs 2.50. The total money made is 265.
  • 1.25s+2.50g=265

<u>Number</u>

  • A total of 155 cups of lemonade were sold. The sum of small cups and large cups sold will equal 155.
  • s+g=155

Here is our system of equations:

1.25s+2.50g=265 \\s+g=155

Now, solve. Let's isolate a variable in the 2nd equation, so we can plug it in after.

  • Subtract g from both sides of the equation.
  • s+g=155
  • s+g-g=155-g
  • s=155-g

Now we know that s is equal to 155-g. We can substitute (155-g) in for s in the first equation.

1.25s +2.50g=265

1.25(155-g)+2.50g=265

Distribute the 1.25

  • 1.25(155-g)= (1.25*155)+ (1.25*-g)= 193.75-1.25g

193.75-1.25g+2.50g=265

Work to isolate the variable. Subtract 193.75 from both sides of the equation and combine like terms on the left.

193.75-1.25g+2.50g=265-193.75       (Subtract 193.75)

-1.25g+2.50g=265-193.75      

1.25g=71.25      (Combine like terms).

1.25 and g are being multiplied. The inverse of multiplication is division. Divide both sides by 1.25

1.25g/1.25=71.25/1.25\\g=71.25/1.25\\g=57

Now we know that 57 large cups were sold. Plug 57 back into the original second equation to find the small cups.

s+g=155

s+57=155

Subtract 57 from both sides of the equation to isolate the variable, s.

s+57-57=155-57\\s=155-57\\s=98

Ashley sold 57 large cups and 98 small cups.

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Answer:

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Step-by-step explanation:

Given

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From the attachment, \angle1 and \angle7 are vertically opposite.

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Answer:

i would say about $1.85

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