Answer:
the answer is an-as-1+1;a,=1
The angle across from A would have to decrease as it should be the same as angle A
For 1 - 12y < 3y+1; y > 15
For 2 - 6y > 4 + 4y; y < -0.2
The given inequalities are:
1 - 12y < 3y + 1
2 - 6y > 4 + 4y
For 1 - 12y < 3y + 1:
1 - 12y < 3y + 1
Collect like terms
-12y - 3y < 1 - 1
-15y < 0
Multiply both sides by -1
-1(-15y) > 0(-y)
15y > 0
Divide both sides by 15
y > 0/15
y > 15
For 2 - 6y > 4 + 4y
Collect like terms
-6y - 4y > 4 - 2
-10y > 2
Multiply both sides by -1
-1(-10y) < 2(-1)
10y < -2
y < -2/10
y < -0.2
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Answer:
Function 1 has the larger maximum at (4, 1)
Explanation:
After observation, graph of function 1 has vertex at Maximum (4, 1)
In order to find vertex of function 2, complete square the equation.
f(x) = -x² + 2x - 3
f(x) = -(x² - 2x) - 3
f(x) = -(x - 1)² - 3 + (-1)²
f(x) = -(x - 1)² - 2
Vertex form: y = a(x - h)² + k where (h, k) is the vertex
So, here for function 2 vertex: Maximum (1, -2)
<h3>Conclusion:</h3>
Function 1 = Maximum (4, 1), Function 2 = Maximum (1, -2)
Function 1 has greater maximum value of (4, 1) as "1 is greater than -2"
It goes into it 0 times but what you can do is 11 going into 12 which would give you 1.1 instead of you making it a remainder. <span />
