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yarga [219]
3 years ago
9

A function g models a relationship in which the dependent variable is multiplied by 4 for every 2 units the independent variable

increases. The value of the function at 0 is 5. Write an equation that represents the function.
Mathematics
1 answer:
12345 [234]3 years ago
6 0
2x+5=y this should be correct.
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The triangle below has an area of 75 units squared. Find the missing side.
Volgvan

Answer:

x = 15 units

Step-by-step explanation:

Here, base of triangle = x units & height = 19 units

Area( \triangle) =  \frac{1}{2}  \times base  \times height \\  \\ 75 =  \frac{1}{2}  \times x \times 10 \\  \\ 75 = x \times 5 \\  \\ x =  \frac{75}{5}  \\  \\ \huge \purple{ \boxed{ x = 15 \: units}}

5 0
3 years ago
Solve for x round to the nearest tenth.
lesantik [10]

Answer:

x ≈ 15.9

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

x² + 6² = 17²

x² + 36 = 289 ( subtract 36 from both sides )

x² = 253 ( take the square root of both sides )

x = \sqrt{253} ≈ 15.9 ( to the nearest tenth )

3 0
2 years ago
Read 2 more answers
9) 19, 17, 15, 13, 11,9,7<br>Rule =​
hodyreva [135]

Answer:

- 2

Step-by-step explanation:

It's a simple rule, all you are doing is subtracting 2 every time.

3 0
3 years ago
Read 2 more answers
A popular chain of superstores made 3.0479×108 dollars in profit last year. One particular store in the chain made 2.102×106 dol
ollegr [7]
This is a simple exercise with rates.
You just have to divide the total profit of the store, that year, per the profit of the particular store.


[3.0479×10⁸ dollars] ÷ [2.102×10⁶ dollars] = 1,45 x 10²





7 0
3 years ago
Find the first derivative?
professor190 [17]
You could do the question the way it is  written, but it is far easier to bring the negative power up to the numerator.

y= x^2 - 3. The derivative of that is
dy/dx = 2x The three is a constant and is always dropped when a derivative is taken
d(-3)/dx = 0

If you are a purist and want to solve the question the way it is written, you could do it this way.

dy/dx = d(1)/dx x^-2 - d(x^-2)/dx * 1
             ======================                    
                          (x^-2)^2

dy/dx =  - (-2 x^ - 3) / x^-4

dy/dx = 2 x^-3 * x^4
dy/dx = 2 x^(-3 + 4)
dy/dx = 2x ^ 1
dy/dx = 2x <<<<< answer
8 0
3 years ago
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