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aleksley [76]
3 years ago
7

y varies inversely with x y = 0.5 when x = 3 What is the value of k, the constant of inverse variation?

Mathematics
1 answer:
Andreas93 [3]3 years ago
4 0
<h3><u>k</u><u> </u><u>=</u><u> </u><u>1</u><u>.</u><u>5</u></h3>

y = k/x

0.5 = k/3

k = 1.5

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-3 & -4;

-3 + (-4) = 7

-3-(-4) = -3+4 = 1

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Help please will mark brainliest!!!!!!
Nimfa-mama [501]
<h3>Solution : </h3>

\bf Speed = \dfrac{\dfrac{4}{5}}{\dfrac{1}{6}}

\bf Speed = \dfrac{4}{5} \times \dfrac{6}{1}

\Large \boxed{\bf Speed = \dfrac{24}{5}}

\pink{\bf So, \: the \: answer \: is \: \dfrac{24}{5} \: miles \: per \: hour}

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What percent of 202 is 34
julia-pushkina [17]

Answer:

Result: 68.68

68.68 is 202% of 34.

Step-by-step explanation:

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202% × 34 = 68.68

Hope it helps :)

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Find the cube root of 1/27
natima [27]

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Expand the function.<br> (2x+y)^(7)
iragen [17]

The binomial (2 · x + y)⁷ in expanded form by 128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷.

<h3>How to expand the power of a binomial</h3>

Herein we have the seventh power of a binomial, whose expanded form can be found by using the binomial theorem and Pascal's triangle. Hence, we find the following expression for the expanded form:

(2 · x + y)⁷

(2 · x)⁷ + 7 · (2 · x)⁶ · y + 21 · (2 · x)⁵ · y² + 35 · (2 · x)⁴ · y³ + 35 · (2 · x)³ · y⁴ + 21 · (2 · x)² · y⁵ + 7 · (2 · x) · y⁶ + y⁷

128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷

Then, the binomial (2 · x + y)⁷ in expanded form by 128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷.

To learn more on binomials: brainly.com/question/12249986

#SPJ1

6 0
1 year ago
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