Question

Find the cube root of 1/27

Answer 1

$\bf \sqrt[3]{\cfrac{1}{27}}~~\begin{cases}1^3=1\\27=3^3\end{cases}\implies \sqrt[3]{\cfrac{1^3}{3^3}}\implies \cfrac{\sqrt[3]{1^3}}{\sqrt[3]{3^3}}\implies \cfrac{1}{3}$

Answer 2

1/3is the answer to this