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4 years ago

Find the cube root of 1/27

2 answers:

8 0

$\bf \sqrt[3]{\cfrac{1}{27}}~~\begin{cases}1^3=1\\27=3^3\end{cases}\implies \sqrt[3]{\cfrac{1^3}{3^3}}\implies \cfrac{\sqrt[3]{1^3}}{\sqrt[3]{3^3}}\implies \cfrac{1}{3}$

storchak [24]4 years ago

5 0

1/3is the answer to this

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Answer:

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3 years ago

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Answer:

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