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Kobotan [32]
3 years ago
12

Find the cube root of 1/27

Mathematics
2 answers:
natima [27]3 years ago
8 0

\bf \sqrt[3]{\cfrac{1}{27}}~~\begin{cases}1^3=1\\27=3^3\end{cases}\implies \sqrt[3]{\cfrac{1^3}{3^3}}\implies \cfrac{\sqrt[3]{1^3}}{\sqrt[3]{3^3}}\implies \cfrac{1}{3}

storchak [24]3 years ago
5 0

1/3is the answer to this

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Step-by-step explanation:

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Answer:

Geometry! Nice!

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This is very simple. In a nutshell, base angles in a isosceles triangle are equal.

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