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SSSSS [86.1K]
3 years ago
5

Given the angles in the diagram, who is closer to the treasure chest and why

Mathematics
2 answers:
Klio2033 [76]3 years ago
5 0
Please see attached file for my answer.
Download docx
Yuki888 [10]3 years ago
3 0

<span>Mia is the one who is closer to the treasure chest. A theorem in Triangle Inequalities state that lines opposite of bigger angles have longer sides. In the case of this triangle, the angle opposite of Mia’s path is smaller than the angle opposite of Nigel’s. To confirm the actual distance, the law of sine and law of cosine can be used.</span>

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A- 6=9. Please help
olchik [2.2K]

Answer:

a = 15

Step-by-step explanation:

6 + 9 = 15

a = 15

15 - 6 = 9

yes

3 0
2 years ago
Read 2 more answers
Someone please help I really appreciate it
Alex_Xolod [135]
So you have to find the relationship between the pumpkin diameter (y) and the number of weeks passed (x) in a table, lets do it taking into account that the equation modeling such behaviour is:
y = 2x + 6, where x is the number of weeks and plus original 6 cm
x                                y                            
week                         diameter
0                                6
1                                8
3                                12
5                                16
10                               26
substitute the x and y values in the equation to see how they fit into it
5 0
2 years ago
Read 2 more answers
A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng
tangare [24]

Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, xy \leq 8000

So,x(220-x) \leq 8000

220x-x^2 \leq 8000

So,220x-x^2 = 8000\\-x^2+220x-8000=0

General quadratic equation : ax^2+bx+c=0

Formula : x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0
3 years ago
Suppose the tree diagram below represents all the students in a high school
Lunna [17]

Answer:

Ok to find the probity we add the amount of boys and the amount of girls together to get 500 and out of these 100 are left handed so 1/5 also know as 20%

Hope This Helps!!!

8 0
3 years ago
Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​,and a standard deviation given by
Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with  

\mu = 62.5 in

\sigma = 2.2 in

the normal probability density function is given by  

f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}, then

(a) P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx = 0.5899

   (in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking P(\bar{X} < 63) where n = 37. \bar{X} is normally distributed with mean 62.5 in and standard deviation 2.2/\sqrt{37}. So, the probability density function is given by

g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}, and

P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0
3 years ago
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