Use a calculator to find the trigonometric value.

john bought a new car for 20,000. if the car depreciates at a rate of 16% each year, what will be the value of the car after 3 y

Lesechka [4]

Answer:

13214

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

RIDDLE ME THIS Fresh and invigorated after completing her algebra homework, Mimi appeared at the living room door. She held a pi

Marat540 [252]

Answer:

Mimi is 15.

Step-by-step explanation:

Set up two equations, and solve by elimination.

2(m+5) = d+5

- 3(m-5) = d-5

_____________

2(m+5) - 3(m-5) = 10

2m + 10 - 3m + 15 = 10

-m + 25 = 10

-m = -15

m = 15

Plug this back in to get dad's age.

2(m+5) = d+5

2(15+5) = d + 5

2(20) = d + 5

40 = d + 5

d = 35

8 0

3 years ago

On a Saturday, Saul can cut 4 lawns in 6 hours. If Mitch can mow lawns at the same rate, how long will it take him to

kotykmax [81]

Answer:

13 1/2 hours

Step-by-step explanation:

4/6=9/x then find the rate and solve

5 0

3 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

Hence, the amount of oil was decreasing at 69300 barrels, yearly

7 0

2 years ago

A rectangular solid with a square base has a volume of 8000 cubic inches. determine the dimensions that yield

stiks02 [169]

A rectangular solid with a square base has a volume of 8000 cubic inches.

6 0

3 years ago