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3 years ago

On a piece of paper, draw a box plot to represent the data below. Then

Mathematics

1 answer:

777dan777 [17]3 years ago

6 0

Since they are already in order you know the 22 and the 61 are the upper and lower extremes. To find the median you find the number that is in the middle which is 42. To find the lower quartile find the middle number starting from the first number and the number to the left of the median (22 and 36 in this case). The loser quartile is 25. To find the upper quartile, fine the middle number between the number to the right of the median and the last number (44 and 61 in this case.) the upper quartile is 57 you then just plot it and graph it

The work is attached

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At NC State University, 16.4% of the undergraduate classes have more than 50 students. If a random sample of 200 undergraduate c

Lena [83]

Answer:

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=200, p=0.164)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

6 0

3 years ago

4.8(x-1.75)= -9.6 but without the distributive property

rosijanka [135]

4.8(x-1.75)= -9.6
Answer:
x=0.55

6 0

3 years ago

Read 2 more answers

Задача

ANEK [815]

Answer:

<h3>Sorry. I can't answer your question because I can't understand that language. Can you put translate it in English? </h3>

5 0

3 years ago

A poll found that 58% of U.S. adult Twitter users get at least some news on Twitter. The standard error for this estimate was 2.

Radda [10]

Answer: (53.49%, 62.51%)

Step-by-step explanation:

Given : A poll found that 58% of U.S. adult Twitter users get at least some news on Twitter.

i.e. p= 0.58

The standard error for this estimate was 2.3%

i.e. S.E.=0.023

Critical value for 95% confidence : $z_{\alpha/2}=1.96$

Confidence interval : $p\pm z_{\alpha/2}(S.E.)$

i.e. $0.58\pm (1.96)(0.023)$

$=0.58\pm 0.04508=(0.58-0.04508,\ 0.58+0.04508)\\\\=(0.53492,\ 0.62508)=(53.492\%,\ 62.508\%)=(53.49\%,\ 62.51\%)$

Conclusion : We are 95% confident that the true population proportion of U.S. adult Twitter users who get some news on Twitter falls in interval (53.49%, 62.51%)

5 0

4 years ago

Joshua uses his thermometer and finds the boiling point of ethyl alcohol to be 75o C. He looks in a reference book and finds tha

Crazy boy [7]

Answer:

the percent error is 6.25%

Step-by-step explanation:

The computation of the percent error is shown below:

Percent error is

= (Experimental value - accepted value) ÷ (experimental value) × 100

= (80 degrees - 75 degrees) ÷ (80 degrees) × 100

= (5 degrees) ÷ (80 degrees) × 100

= 0.0625 × 100

= 6.25%

hence, the percent error is 6.25%

We simply applied the above formula so that the correct value could come

And, the same is to be considered

5 0

3 years ago

Read 2 more answers