Answer:
m<IJL = 48
Step-by-step explanation:
<IJL = x
100 - 52 = x
x = 48
Answer:
1 = The Value of the expression is 10 for x = 3 and y = 2
2 = The Value of the expression is 10 for x = 3 and y = 2
3 = The Value of the expression is 10 for x = 2 and y = 3
4 = The Value of the expression is 10 for x = 2 and y = 3
5 = The Value of the expression is 10 for x = 2 and y = 3
6 = The Value of the expression is 10 for x = 3 and y = 2
Srry if im wrong
Answer:
x=-3
Step-by-step explanation:
2
−
1
⋅
1
2
=
6
2-1 \cdot \frac{12}{x}=6
2−1⋅x12=6
Solve
1
Combine multiplied terms into a single fraction
2
−
1
⋅
1
2
=
6
2
+
−
1
⋅
1
2
=
6
2
Multiply the numbers
2
+
−
1
⋅
1
2
=
6
2
+
−
1
2
=
6
3
Subtract
2
2
2
from both sides of the equation
2
+
−
1
2
=
6
2
+
−
1
2
−
2
=
6
−
2
4
Simplify
Subtract the numbers
Subtract the numbers
−
1
2
=
4
5
Multiply all terms by the same value to eliminate fraction denominators
−
1
2
=
4
⋅
−
1
2
=
⋅
4
6
Simplify
Cancel multiplied terms that are in the denominator
Re-order terms so constants are on the left
−
1
2
=
⋅
4
-12=x \cdot 4
−12=x⋅4
−
1
2
=
4
-12=4x
−12=4x
−
1
2
=
4
7
Divide both sides of the equation by the same term
−
1
2
=
4
−
1
2
4
=
4
4
8
Simplify
Divide the numbers
Cancel terms that are in both the numerator and denominator
Move the variable to the left
=
−
3
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Solution
=
−
3
2cos²x+cos x-1=0
cos x=t
2t²+t-1=0
t=[-1⁺₋√(-1+8)]/2=(-1⁺₋3)/4
We have two possible set solutions:
First set solutions.
t₁=(-1-3)/2=-4/4=-1
cos x=-1 ⇒x=cos⁻¹ (-1)=π +2kπ or 180º+360ºk (k=(...-2,-1,0,1,2...)
Second set solutions:
t₂=(-1+3)/4=2/4=1/2
cos x=1/2 ⇒ x=cos⁻¹ 1/2=π/3+2kπ U 5π/3+ 2kπ or
60º+360ºK U 300º+360ºK (k=...-2,-1,0,1,2,...)
solutions: first set solutions U second set solutions:
Answer in radians : π +2kπ U π/3+2kπ U 5π/3+ 2kπ (k=...-1,0,1,...)
Answer is degrees: 180º+360ºk U 60º+360ºK U 300º+360ºK (k=...-2,-1,0,1,2,...)
