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Alisiya [41]
3 years ago
10

The following are a list of variables that will almost certainly vary across students in a large undergraduate introductory stat

istics course.
(a) Favorite beverage
(b) Year of birth
(c) Typing speed
(d) Handedness (e.g., left or right-handed)
(e) Age
(f) Occupation
(g) Self-report of Assertiveness
For questions 1a to 1d that follow choose the variable or variables that best represent the level of measurement.
a) Which variables would typically be measured on a nominal scale of measurement?
b) Which variable would likely be measured on an interval, but not a ratio scale?
c) Which two variables are most likely to be measured on a ratio scale?
d) As typically measured, which variable represents at least an ordinal scale of measurement, but probably not a true interval scale?
Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0

Answer:

a.) Favorite Beverage, Handedness, Occupation.

b.) Year of birth

c.) Age and typing speed

d.) Self-report of Assertiveness

Step-by-step explanation:

Scales of measurements are used in statistics to classify variables. The scale of measurement of a variable is important in statistics because it determines the kind of satisfaction analysis that should be used on it.

The four types of scale of measurement are;

1.) Norminal Scale: The normal scale is a categorical scale where variables are labeled with no specific order. No calculations can be done on this type of measurement because they do not have values and there is usually no order. Examples include;

Occupation, Favorite Beverage and Handedness.

2.) Ordinal Scale: This is used to show the order of variables. It is similar to the norminal scale with a slight difference. The ordinal scale has some form of ranking, that is some variables will be considered better or higher than others. Example include;

Self-report of assertiveness. Someone that claims to be highly assertive can be ranked above one that is just assertive.

3.) Interval Scale: This kind of measurements shows definite intervals between variables. It is like a scale where the order and the difference between variables are shown with no true zero value. Variables that fall under this category include; temperature and year of birth.

4.) Ratio Scale: This is the most accurate scale of measurement that encompasses the norminal, ordinal and interval scale of measurement. It has a zero value, shows order, interval and can still categorized. And example is the Age of students and typing speed.

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A rectangular metal plate is measured to be 7.6cm long and 3.1cm wide, both correct to one decimal place.
ElenaW [278]

Answer:

We know that the rectangular plate has measures of:

length = 7.6 ± 0.05 cm

width = 3.1 ± 0.05 cm

(the error is 0.05cm because we know that both measures are correct to one decimal place)

First, the upper bound of the length is equal to the measure of the length plus the error, this is:

L = 7.6 cm + 0.05 cm = 7.65 cm

The upper bound of the area is the area calculated when we use the upper bound of the length and the upper bound of the widht.

Remember that the area for a rectangle of length L and width W, is:

A = W*L

Then the upper bound of the area is:

A = (7.6cm + 0.05cm)*(3.1cm + 0.05cm) = 10.8 cm^2

5 0
3 years ago
You can only divide a numerator and denominator one time when finding the simplest form.
morpeh [17]
False. Its as many times until you can no longer divide
8 0
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Solve for x: -4x – 12 > 36 A. x > -12 B. x > 12 C. x < -12 D. x < 12
Nataliya [291]

Answer: x < -12

Step-by-step explanation:

-4x – 12 > 36

4x > 36+ 12

-4 > 48

x < -48/4

x < -12

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Sarah has 284 coins in a piggy bank with a total value of $22.78. Sarah has 173 pennies, 5 more dimes than nickels, the rest are
pickupchik [31]
Let P = number of coins of pennies (1 penny = 1 cent)
Let N = number of coins of nickels (1 nickel = 5 cents)
Let D = number of coins of dimes (1 dime = 10 cents)
Let Q = number of coins of quarters (1 quarter = 25 cents)

a) P + N + D + Q = 284 coins, but P = 173 coins, then:
173 + N + D + Q =284 coins
(1)  N + D + Q = 111 coins

b) D = N + 5 OR D - N =5 coins
(2) D - N = 5 coins

c) Let's find the VALUE in CENTS of (1) that is N + D + Q = 111 coins
5N + 10D + 25 Q = 2,278 - 173 (1 PENNY)
(3) 5N + 10D + 25Q = 2105 cents
Now we have 3 equation with 3 variables:

(1)  N + D + Q = 111 coins
(2) D - N = 5 coins
(3) 5N + 10D + 25Q = 2105 cents
Solving it gives:
17 coins N ( x 5 = 85 cents)
22 coins D ( x 10 = 220 cents)
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and 173 P,
proof:
that makes a total of 85+2201800+172 =2,278 c or $22.78




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