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solong [7]
3 years ago
8

Please answer as soon as possible, whoever is first gets the brainliest

Mathematics
1 answer:
Jlenok [28]3 years ago
7 0

Answer:

I'm not sure what to do here

Step-by-step explanation:

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Solve the following for the specified variable<br><br> Z=s/2(P+p); for P
lapo4ka [179]

Answer:

\boxed{\sf P = \frac{2Z}{s} - p}

Step-by-step explanation:

\sf Solve \ for \ P: \\ \sf \implies  Z = \frac{s}{2} (P + p) \\ \\ \sf Z = \frac{s}{2} (P + p) \ is \ equivalent \ to \ \frac{s}{2} (P + p) = Z: \\ \sf \implies \frac{s}{2} (P + p) = Z \\ \\  \sf Divide \ both \ sides \ by \ \frac{s}{2} : \\ \sf \implies P + p = \frac{2Z}{s} \\ \\ \sf Substrate \ p \ from \ both \ sides: \\ \sf \implies P = \frac{2Z}{s} - p

6 0
3 years ago
What is AB in the figure?
sweet [91]

Answer:

Angle Bisector

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
The length of a rectangular floor is 4 feet longer than its width w. The area of the floor is 525 ft^2.
andre [41]

Answer:

  • 525 = (w+4)(w)
  • 21 ft by 25 ft

Step-by-step explanation:

Let w represent the width of the floor. Then the length of the floor is (w+4) and its area is ...

  A = LW

  525 = (w+4)(w)

  w^2 +4w -525 = 0

  (w -21)(w +25) = 0 . . . . factor the above

Solutions are ...

  w = 21, w = -25

We are interested in the positive solution: w = 21.

The floor is 21 feet wide and 25 feet long.

_____

<em>Alternate solution</em>

Sometimes, when the factors aren't obvious, it works well to write an equation for the average of the dimensions. Here, we can represent that with x, and use (x-2) for the width, and (x+2) for the length. Then we have ...

  525 = (x-2)(x+2) = x^2 -4

  529 = x^2

  √529 = 23 = x

Then w=23 -2 = 21, and the length is w+4 = 25.

7 0
3 years ago
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Whats 5a - 2a + 9 ? <br>could someone add how you got the answer to please?
Vinvika [58]
Step 1. Simplify 
3a+9

3a+9 is your answer:

Done! :)

7 0
3 years ago
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Find the approximate area of the composite figure below
Readme [11.4K]
<h3> Δ</h3><h3> <u>E</u><u>X</u><u>A</u><u>M</u><u>P</u><u>L</u><u>E</u></h3>

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<h3>I hope i can help</h3>

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2 years ago
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