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2 years ago

A system of equations is shown:

Mathematics

1 answer:

Harrizon [31]2 years ago

6 0

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x=-y+6&(1)\\-4x+3y=8&(2)\end{array}\right\\\\(1)\\-y+6=2x\qquad\text{subtract 6 from both sides}\\-y=2x-6\qquad\text{change the signs}\\y=6-2x\\\\\text{substitute it to (2):}\\\\(2)\\-4x+3(6-2x)=8\qquad\text{use the distributive property}\\-4x+(3)(6)+(3)(-2x)=8\\-4x+18-6x=8\qquad\text{subtract 18 from both sides}\\-10x=-10\qquad\text{divide both sides by (-10)}\\x=1\\\\\text{put the value of x to (1):}\\\\y=6-2(1)\\y=6-2\\y=4$

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Write the following numbers in order, putting the largest

fiasKO [112]

Answer:

31.53

31.099

31.009 ⬅ (I'm assuming this one is a decimal too)

0.03

0.009

0.007

Explanation:

Here ya go.

Hope this helps :)

5 0

2 years ago

SAT math scores have a bell-shaped distribution with a mean of 515 and a standard deviation of 114.

nadezda [96]

Hey there mate :)

Analysis :

$401 = 515 - 114 = u - 6$

And

$173 = 515 - 3.114 = u - 36$

$= \frac{p(u - 36 < u < u + 36) - p(u - 6 < u < u + 6)}{2}$

$= \frac{99.73percent - 68.21percent}{2}$

$= \frac{31.46percent}{2}$

$= {15.73percent}$

Then, calculating,

$u - 26 = 515 - 2 \times 114 = 287$

And

$u + 26 = 515 + 2 \times 114 = 743$

Then,

$The \: Range = (287,743)$

Final Answers :-

15.73 %

(287,743)

~Benjemin360

3 0

2 years ago

Determine which graph represents a reflection across the x-axis of f(x) = 3(1.5).

Ghella [55]

Step-by-step explanation:

fill in the missing fraction parts

4 0

1 year ago

X = –14.6 and y = 2.5. –x – |y|

vaieri [72.5K]

Get on algebra calculator (mathpapa) and you should get the answer

8 0

3 years ago

Read 2 more answers

If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"

seraphim [82]

Answer:

$a + b + c = \pi \\ = > c= \pi - a - b \\ < = > \tan(c) = \tan(\pi - a - b) = -\tan(a + b)$

Step-by-step explanation:

we have:

$\tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)$

we also have:

$\tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)$

from (1)(2) => proven

5 0

2 years ago