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horrorfan [7]
3 years ago
10

when was the balloon at 250 ft ? make sure you describe all times when the balloon was at this height.

Mathematics
1 answer:
Alexxx [7]3 years ago
7 0

Answer: A. You need two functions, one for each balloon:

Let h be height, in ft.

Let t be time, in min.

Balloon 1:

h1 = 250 (starting height) + 110t (rate that height is increasing)

Step-by-step explanation:

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strojnjashka [21]

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Step-by-step explanation:

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3 years ago
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A ball is dropped from a height of 192 inches onto a level floor. After the third bounce it is still 3 inches off the ground. Pr
ANEK [815]

Answer: The required fraction = \dfrac18

Step-by-step explanation:

Let the required fraction = \dfrac{p}{q}

Given: Initial height = 192 inches

Height of ball after second bounce = \dfrac{p}{q}\times192

Height of ball after third bounce = \dfrac{p}{q}\times\dfrac{p}{q}\times192=192\dfrac{p^2}{q^2}

After the third bounce it is 3 inches off the ground.

So,

(\dfrac{p}{q})^2192=3\\\\\\(\dfrac{p}{q})^2=\dfrac{3}{192}\\\\(\dfrac{p}{q})^2=\dfrac{1}{64}\\\\(\dfrac{p}{q})^2=(\dfrac{1}{8})^2\\\\ \dfrac{p}{q}=\dfrac{1}{8}

Hence, The required fraction = \dfrac18

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3 years ago
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