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horrorfan [7]
4 years ago
10

when was the balloon at 250 ft ? make sure you describe all times when the balloon was at this height.

Mathematics
1 answer:
Alexxx [7]4 years ago
7 0

Answer: A. You need two functions, one for each balloon:

Let h be height, in ft.

Let t be time, in min.

Balloon 1:

h1 = 250 (starting height) + 110t (rate that height is increasing)

Step-by-step explanation:

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What is the Greatest Common Factor of 12 and 36? (1 point)
madreJ [45]

Answer: D) 12

The factors of 12 are: 1, 2, 3, 4, 6, 12

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

The greatest common factor is 12.

6 0
3 years ago
Read 2 more answers
Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

\bar {x}_1 = 13.5

\bar {x}_2 = 12

σ₁ = 2.5

σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

8 0
3 years ago
Help me please!! worth 12 points
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To be honest  the numbers up there are like dividing like it say 2 or -2 so i would be 2/-2 i hope these helps i really do 
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4 years ago
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7 0
3 years ago
which expression is equivalent to 100 n2 − 1? (10n)2 − (1)2 (10n2)2 − (1)2 (50n)2 − (1)2 (50n2)2 − (1)2
Wewaii [24]

You know that 100=10^2.

Use the property (ab)^2=a^2\cdot b^2 to state that

100n^2=10^2\cdot n^2=(10n)^2.

Then the expression 100n^2-1 is equivalent to

(10n)^2-1=(10n)^2-1^2.

Answer: correct choice is A.

5 0
3 years ago
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