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USPshnik [31]
3 years ago
12

Need help asap please

Mathematics
1 answer:
saveliy_v [14]3 years ago
5 0

Answer:

\displaystyle no

Step-by-step explanation:

We do not have enough information to use this theorem. We only have one side and two <em>right</em><em> </em><em>angles</em> marked. Hence, you have your answer.

I am joyous to assist you at any time.

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Reflect shape A in the line y = x.
marshall27 [118]

Answer:

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8 0
2 years ago
F(x)=2x^2-5;find when f(x)=-7​
Daniel [21]

Answer:

x=i or no solution exists depending on the user's grade

Step-by-step explanation:

f(x) = 2x^2-5

-7 = 2x^2-5

-2 = 2x^2, x^2=-1, x=i

6 0
2 years ago
Read 2 more answers
A travel agent currently has 80 people signed up for a tour. The price of a ticket is $5000 per person. The agency has chartered
Nikolay [14]
So hmm let's take a peek at the cost first

so, they chartered the plane for 150 folks with a fixed cost of 250,000
now, incidental fees are 300 per person, if we use the quantity "x", for how many folks, then if "x" persons are booked, then incidental fees are 300x

so, more than likely an insurance agency is charging them 300x for coverage

anyway, thus the cost C(x) = 250,000 + 300x

now, the Revenue R(x), is simple is jut price * quantity

well, the price, thus far we know is 5000 for 80 folks, but it can be lowered by 30 to get one more person, thus increasing profits

so... let's see what the price say y(x) is  \bf \begin{array}{ccllll}&#10;quantity(x)&price(y)\\&#10;-----&-----\\&#10;80&5000\\&#10;81&4970\\&#10;82&4940\\&#10;83&4910&#10;\end{array}\\\\&#10;-----------------------------\\\\

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;&({{ 80}}\quad ,&{{ 5000}})\quad &#10;%   (c,d)&#10;&({{ 83}}\quad ,&{{ 4910}})&#10;\end{array}&#10;\\\quad \\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-90}{3}\implies -30&#10;\\ \quad \\\\&#10;% point-slope intercept&#10;y-{{ 5000}}={{ -30}}(x-{{ 80}})\implies y=-30x+2400+5000\\&#10;\left.\qquad   \right. \uparrow\\&#10;\textit{point-slope form}&#10;\\\\\\&#10;y=-30x+7400

so.. now we know y(x) = -30x+7400

now, Revenue is just price * quantity
the price y(x) is -30x+7400, the quantity is "x"

that simply means R(x) = -30x²+7400x


now, for the profit P(x)

the profit is simple, that is just incoming revenue minus costs, whatever is left, is profit
so P(x) = R(x) - C(x)

P(x) = (7400x - 30x²) - (250,000+300x)

P(x) = -30x² + 7100x - 250,000

now, where does it get maximized? namely, where's the maximum for P(x)?

well \bf \cfrac{dp}{dx}=-60x+7100

and as you can see, if you zero out the derivative, there's only 1 critical point, run a first-derivative test on it, to see if its a maximum
7 0
3 years ago
Solve the system of equations:
Simora [160]

Answer:

x1=6 , x2=1

Step-by-step explanation:

If you have any questions about the way I solved it,don't hesitate to ask

8 0
3 years ago
Find the missing dimension.
Alecsey [184]

Answer:

2 m

Step-by-step explanation:

Here the area and the lengths of the two parallel sides of this trapezoid are given:

A = 7m^2, b1 = 3 m and b2 = 4 m.  What's missing is the width of the trapezoid.

First we write out the formula for the area of a trapezoid:

       b1 + b2

A = --------------- * w, where w represents the width of the figure.

             2

We need to solve this for the width, w.  Multiplying both sides of the above equation by

     2

------------

b1 + b2

results in

 2A

------------ = w

b1 + b2

Substituting 7 m^2 for A, 3 m for b1 and 4 m for b2 results in

        2(7 m^2)           14 m^2

w = ------------------ = ---------------- = 2 m

        (3 + 4) m             7 m

The missing dimension is the width of the figure.  This width is 2 m.

4 0
3 years ago
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