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iogann1982 [59]
1 year ago
14

Calculate the volume of water in the cup when it is full

Mathematics
1 answer:
maxonik [38]1 year ago
7 0

To find:

The volume of the water in the cup when it is full.

Solution:

The volume of the water is equal to the difference of the volume of the small cone and the larger cone.

Here, the ratio of the radius of both cones is equal to the ratio of their heights. SO,

\begin{gathered} \frac{r}{2.7}=\frac{20}{20-8} \\ \frac{r}{2.7}=\frac{20}{12} \\ \frac{r}{2.7}=\frac{5}{3} \\ r=4.5 \end{gathered}

The radius of the larger cone is 4.5 cm.

So, the volume of the water is:

\begin{gathered} V=\frac{1}{3}\pi R^2H-\frac{1}{3}\pi r^2h \\ =\frac{1}{3}\pi(R^2H-r^2h) \\ =\frac{1}{3}\pi((4.5)^2(20)-(2.7)^2(12)) \\ =\frac{1}{3}\cdot\frac{22}{7}(405-87.48) \\ =\frac{22}{21}(317.52) \\ =332.64cm^2 \end{gathered}

The volume of water when the cup is full is 332.64 cm^2.

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D and E

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Answer:

y=2(x+6)^2+7

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Step-by-step explanation:

y=2x^2+24x+79

Completing the square is a process of converting a quadratic equation in standard form into vertex form.

The first step in completing the square is grouping the quadratic and linear terms of the quadratic equation.

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y=2(x^2+12x)+79

Now complete the square, add a term to make the grouped part of the equation a complete square, then balance the equation.

y=2(x^2+12x+36-36)+79

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y=2(x+6)^2+79-72

y=2(x+6)^2+7

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Ross paints a wall in her bedroom she puts green paint on 5/8 of the wall and blue paint on 3/8 of the wall which of the followi
valina [46]

Both of the fractions can be added since they both have 8 as the denominator 3/8+5/8=8/8 which is a whole.


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3 years ago
Jim was thinking of a number. Jim halves the number and gets an answer of 61.2. Form an equation with
ioda

Answer:

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2 years ago
Help me solve this please
shutvik [7]

Answer:

D'G' = 52.5 units

Step-by-step explanation:

Since the dilatation is centred at the origin then multiply the original coordinates by the scale factor 3.5

D' = (1 × 3.5, 7 × 3.5 ) = (3.5, 24.5 )

G' = (- 8 × 3.5, - 5 × 3.5 ) = (- 28, - 17.5 )

Calculate D'G' using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = D' (3.5, 24.5) and (x₂, y₂ ) = G' (- 28, - 17.5)

D'G' = \sqrt{(-28-3.5)^2+(-17.5-24.5)^2}

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        = \sqrt{2756.25}

         = 52.5 units

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2 years ago
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