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11 months ago

Calculate the volume of water in the cup when it is full

Mathematics

1 answer:

maxonik [38]11 months ago

7 0

To find:

The volume of the water in the cup when it is full.

Solution:

The volume of the water is equal to the difference of the volume of the small cone and the larger cone.

Here, the ratio of the radius of both cones is equal to the ratio of their heights. SO,

$\begin{gathered} \frac{r}{2.7}=\frac{20}{20-8} \\ \frac{r}{2.7}=\frac{20}{12} \\ \frac{r}{2.7}=\frac{5}{3} \\ r=4.5 \end{gathered}$

The radius of the larger cone is 4.5 cm.

So, the volume of the water is:

$\begin{gathered} V=\frac{1}{3}\pi R^2H-\frac{1}{3}\pi r^2h \\ =\frac{1}{3}\pi(R^2H-r^2h) \\ =\frac{1}{3}\pi((4.5)^2(20)-(2.7)^2(12)) \\ =\frac{1}{3}\cdot\frac{22}{7}(405-87.48) \\ =\frac{22}{21}(317.52) \\ =332.64cm^2 \end{gathered}$

The volume of water when the cup is full is 332.64 cm^2.

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Regular hexagon ABCDEF is inscribed in circle X and has an apothem that is 6√3 inches long. Use the length of the apothem to cal

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Answer:

Part A

$The \ circumradius, \ R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}$

Plugging in the given values we get;

$The \ circumradius, \ R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3} \times \dfrac{2}{\sqrt{3} } = 12$

R = 12 inches

The radius of the circumscribing circle is 12 inches

Part B

The length of each side of the hexagon, 's', is;

$s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)$

Therefore;

$s = 6 \cdot \sqrt{3} \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3} \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12$

s = 12 inches

The perimeter, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon is 72 inches

Step-by-step explanation:

The given parameters of the regular hexagon are;

The length of the apothem of the regular hexagon, a = 6·√3 inches

The relationship between the apothem, 'a', and the circumradius, 'R', is given as follows;

$a = R \cdot cos \left(\dfrac{\pi}{n} \right)$

Where;

n = The number of sides of the regular polygon = 6 for a hexagon

'a = 6·√3 inches', and 'R' are the apothem and the circumradius respectively;

Part A

Therefore, we have;

$The \ circumradius, \ R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}$

Plugging in the values gives;

The circumradius, R = 12 inches

Part B

The length of each side of the hexagon, 's', is given as follows;

$s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)$

Therefore, we get;

$s = 6 \cdot \sqrt{3} \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3} \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12$

The length of each side of the hexagon, s = 12 inches

The perimeter of the hexagon, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon = 72 inches

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