Write the word sentence as an equation. A number k increased by 7 is 34.

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0

3 years ago

How would I finish solving this?

Zarrin [17]

Hello!

The original equation is:

200 = (5w ÷ 2)8

This problem can be written as:

200 = (5w/2)8

And you can then reduce the numbers with 2:

200 = 5x * 4
200 = 20x
10 = x

Your correct answer is 10.

3 0

3 years ago

Read 2 more answers

If g(x) = 3x + 2 and h(x) = 9x2 + 12x + 6, find a function f such that f ○ g = h

Virty [35]

F(g(x)) = f(3x+2) = h(x)=9x^2+12x + 6

Note that (3x+2)^2 = 9x^2 + 12x + 4, which is almost, but not quite, equal to h(x).

Let's experiment. What if f(x) = x^2 + 2?

Then f(3x+2) = (3x+2)^2 + 2 = 9x^2 + 12x + 4 + 2 = 9x^2 + 12x + 6, which is the same as the given h(x).

Thus, f(x) is x^2 + 2.

6 0

4 years ago

An artist is creating a sculpture using bendable metal rods of equal length. One rod is formed into the shape of a square and an

Alika [10]

Check the picture below.

so notice, their perimeter is the same, because the perimeter is just one rod anyway, and all rods are the same length, thus

$\bf P_s=P_t\implies 4s=3(s+2)\implies 4s=3s+6\implies s=6$

6 0

3 years ago

Read 2 more answers

The owner of a local golf course wants to estimate the difference between the scores of golfers on his golf course and the score

Olenka [21]

Answer:

(8) The correct option is (3).

(2) The correct option is (1).

Step-by-step explanation:

(8)

The hypothesis can be defined as:

H₀: There is no difference between the two population means, i.e. μ₁ = μ₂.

Hₐ: There is a difference between the two population means, i.e. μ₁ ≠ μ₂.

The decision rule of the test based on confidence interval is:

If the (1 - α) % confidence interval consists the null hypothesis value then the null hypothesis is not rejected. and vice-versa.

The 90% confidence interval for the paired difference between means is, (-3.31, 14.74).

The interval consists the null value, 0.

Thus, the null hypothesis was failed to be rejected.

Conclusion:

No significant difference exists between the average difference in scores and the differences were calculated as 0.

Thus, the correct option is (3).

(2)

A (1 - α) % confidence interval implies that there is (1 - α) % chance of the population parameter to be contained in this interval.

Or if 100 such intervals are constructed then (1 - α) of these intervals will consist the true parameter value.

The 99% confidence interval for the difference between means is, (-0.124, 13.85).

This interval implies that the true mean difference between the two populations lies in this interval with probability 0.99.

Conclusion:

We are 99% confident that the difference between the average age of all men and all women who play golf at the course is between -0.124 and 13.85.

Thus, the correct option is (1).

4 0

3 years ago