<span>The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers.
1st: 2x
2nd: 2x+2
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EQUATION:
2x =(1/2)(2x+2)+10
2x = x + 11
x = 11
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1st: 2x = 22
2nd: 2x + 2 = 24
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2) The greater of two consecutive even integers is 6 less than the times the lesser
</span><span>3) Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91.
1st: x
2nd: x+1
3rd: x+2
4th: x+3
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EQUATION:
2(x+2 + x+3) = 3x + 91
4x + 12 = 3x + 91
x = 79
x+1 = 80
etc.
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4) Find a set of four consecutive positive integers such that the greatest integer in the set is twice the least integer in the
I'll leave this to you.</span>
Answer:
93
Step-by-step explanation:
by remainder theorem p(3) is the remainder
and therefore it is 93
Answer:
x=11.5
Step-by-step explanation:
2x+8=-15
x=-23/2
x=-11.5
