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olya-2409 [2.1K]
3 years ago
12

If ADE ABC in this diagram, which pair of ratios must necessarily be equal?

Mathematics
2 answers:
ad-work [718]3 years ago
8 0

Answer:

\frac{AD}{AB}=\frac{AE}{AC}=\frac{DE}{BC}

Step-by-step explanation:

we know that

Triangle ADE and Triangle ABC are similar

therefore

the ratio of their corresponding sides are equal

so

\frac{AD}{AB}=\frac{AE}{AC}=\frac{DE}{BC}

solong [7]3 years ago
4 0
From the diagram, the the pair of ratios that should be equal is the ratio between the sides of each triangle. For instance,

AE/EC = AD/DB

This ratio of the lengths should be equal so that the figure can be true. Hope this answers  the question.
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HELP PLZZZZZZZZZZZZ!!!!!!!!!!!!!!!! <br> ILL GIVE YOU 15 POINTS
seropon [69]

Answer:

B

Step-by-step explanation:

a rational number is a number that can be expressed as a fraction p/q of two integers, q cannot be 0

so for A

\sqrt{4/5} Cannot be expressed as 2 integers as a quotient

so A is wrong

For B .125 is 1/8 so yes -2 is a integer so yes 2/5 are 2 integers so yes

and \sqrt{16/9} Is 4/3 so yes

B

7 0
3 years ago
80% is best represented by which the following fractions<br> A. 8/100<br> B.4/5<br> C.3/4<br> D.8/10
gladu [14]

Answer:

d!

Step-by-step explanation:

6 0
3 years ago
Could someone answer this please? thanks a lot
Mila [183]

Answer:

8$

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Kaya used these steps to solve the equation 7 + 2x = 2(x - 1) + 4. Which choice describes the meaning of her result, 7 = 2?
Whitepunk [10]

Answer is A

7 + 2X = 2(X-1) + 4

7 + 2X = 2X-2+4

7 + 2X = 2X + 2 whether 2X = 2X-5  or 5 + 2X = 2X still  0 = 5 Or 0= -5 which is not possible

4 0
3 years ago
Read 2 more answers
The arch beneath a bridge is​ semi-elliptical, a​ one-way roadway passes under the arch. The width of the roadway is 38 feet and
forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

\frac{x^2}{a^2}+\frac{y^2}{b^2}

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

a=\frac{38}{2}=19ft

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}

and we can simplify the equation, so we get:

\frac{x^2}{361}+\frac{y^2}{144}

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

\frac{y^{2}}{144}=1-\frac{x^{2}}{361}

y^{2}=144(1-\frac{x^{2}}{361})

we can add everything inside parenthesis so we get:

y^{2}=144(\frac{361-x^{2}}{361})

and take the square root on both sides, so we get:

y=\sqrt{144(\frac{361-x^{2}}{361})}

and we can simplify this so we get:

y=\frac{12}{19}\sqrt{361-x^{2}}

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

y=\frac{12}{19}\sqrt{361-(8)^{2}}

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.

5 0
3 years ago
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