This is the answer y=-4x-4
<u>Options</u>
- Counting rule for permutations
- Counting rule for multiple-step experiments
- Counting rule for combinations
- Counting rule for independent events
Answer:
(C)Counting rule for combinations
Step-by-step explanation:
When selecting n objects from a set of N objects, we can determine the number of experimental outcomes using permutation or combination.
- When the order of selection is important, we use permutation.
- However, whenever the order of selection is not important, we use combination.
Therefore, The counting rule that is used for counting the number of experimental outcomes when n objects are selected from a set of N objects where order of selection is not important is called the counting rule for combinations.
Hello!
The problem has asked that we write a
point-slope
equation of the line in the image above.
Point-Slope Form uses the following formula:
y –

= m(x –

)
In this case, M represents the
slope while

and

represent the
corresponding X and Y values of any given point on the line.
We are given that the slope of the line is -

. We also know that any given point on a graph takes the form (x,y). Based on the single point provided in the image above, we can determine that

is equal to
6 and

is equal to
2. Now insert all known values into the point-slope formula above:
y – 2 = -

(x – 6)
We have now successfully created an equation based on the information given in the problem above. Looking at the four possible options, we can now come to the conclusion that
the answer is C.
I hope this helps!
Step-by-step explanation:
To find a ratio, you have to divide a next terms with before terms.
A1 = 35/2
A2 = 7
ratio = A2 ÷ A1
ratio = 7 ÷ 35/2
ratio = 7 × 2/35
ratio = 14/35 = 0,4
Ratio = 0,4
Answer:
Below.
Step-by-step explanation:
I won't do all of these for you but I'll show you the general method.
First write each number as prime factors.
For example number 7:
LCM of 24 and 34.
24 = 2 * 2 * 2 * 3
34 = 2 * 17
The LCM is the multiple of all these factors EXCEPT if there is a duplicate number you only use it once.
There is one duplicate here - the 2 ( in bold) so we only use this once.
So the LCM = 2 * 2 * 2 * 3 * 17 = 408.
Number 1:
13, 25
13 = 13
25 = 5 * 5
There are no duplicates so the LCM = 13 * 5 * 5 = 325.
Number 18:
15, 84
15 = 3 * 5
84 = 2 * 2 * 3 * 7
Number 3 is common to both sets so it is only used once:
LCM = 2 * 2 * 3 * 5 * 7 = 420.
Number 40:
18, 48
18 = 2 * 3 * 3
48 = 2 * 2 * 2 * 2 * 3
There are 2 sets of duplicates here, 2 and 3 .
LCM = 2 * 2 * 2* 2 * 3 * 3 = 144.