Which of the following could be the shape of the cross section of the cone?

A line passes through the points (-4, -3) and (2,6). Determine the slope of the line

Grace [21]

Slope is 1/2. The equation to solve it is y2-y1 / x2-x1. I hope you understand it now :)

4 0

3 years ago

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HELP ILL GIVE BRAINLIEST

SVETLANKA909090 [29]

Answer:

$\huge\boxed{\bf\:c = \frac{11}{4}}$

Step-by-step explanation:

$4c + 2c = 4c + \frac{11}{2}$

Cancel 4c on both the sides of the equation.

$2c = \frac{11}{2}$

Bring the 2 in the denominator of 11/2 to the left hand side of the equation.

$2*2c = 11\\4c = 11$

Bring 4 to the right hand side if the equation.

$\boxed{\bf\:c = \frac{11}{4}}$

$\rule{150pt}{2pt}$

4 0

1 year ago

Hello, no rush, but I need to know the answer for 4(x-2+y)

bixtya [17]

Answer:

It's 4x - 8 + 4y

Step-by-step explanation:

4(x-2+y)

4 (x) = 4x

4 (2) = 8

4 (y) = 4y

4x - 8 + 4y

3 0

3 years ago

A tank initially has 300 gallons of a solution that contains 50 lb. of dissolved salt. A brine solution with a concentration of

belka [17]

Let s(t) be the amount of salt in the tank at time t. Then s(0) = 50 lb.

Salt flows into the tank at a rate of

(2 gal/min) (6 lb/gal) = 12 lb/min

and flows out at a rate of

(2 gal/min) (s(t)/300 lb/gal) = s(t)/150 lb/min

so that the net rate at which salt is exchanged through the tank is

ds(t)/dt = 12 - s(t)/150 … (lb/min)

Solve for s(t). The DE is separable, so we have

ds/dt = 12 - s/150

150 ds/dt = 1800 - s

150/(1800 - s) ds = dt

Integrate both sides to get

-150 ln|1800 - s| = t + C

Solve for s :

ln|1800 - s| = -t/150 + C

1800 - s = exp(-t/150 + C )

1800 - s = C exp(-t/150)

s = 1800 - C exp(-t/150)

Now given that s(0) = 50, we solve for C :

50 = 1800 - C exp(-0/150)

50 = 1800 - C

C = 1750

Then the amount of salt in the tank at any time t ≥ 0 is

s(t) = 1800 - 1750 exp(-t/150)

To find the time it takes for the tank to hold 100 lb of salt, solve for t in

100 = 1800 - 1750 exp(-t/150)

1700 = 1750 exp(-t/150)

34/35 = exp(-t/150)

ln(34/35) = -t/150

t = -150 ln(34/35) ≈ 4.348

So it would take approximately 4.348 minutes.

By the way, we didn't have to solve for s(t), we could have instead stopped with

-150 ln|1800 - s| = t + C

Solve for C - this C is not the same as the one we found using the other method. s(0) = 50, so

-150 ln|1800 - 50| = 0 + C

C = -150 ln|1750|

==> t = 150 ln(1750) - 150 ln|1800 - s|

Then s(t) = 100 lb when

t = 150 ln(1750) - 150 ln(1700)

t = 150 ln(1750/1700)

t = 150 ln(35/34)

t ≈ 4.348

5 0

3 years ago

Select all that have a value of 0. Cost cos 0 sin 0 sin 34 tan x DONE

olga nikolaevna [1]

Answer:

sin 0

and tan x when x =0

will provide a value of 0

8 0

3 years ago

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