Answer:
c = 5505263.16 J/g.°C
Explanation:
Given data:
Mass of ring = 12 mg (12/1000 = 0.012 g)
Calories used = 30.0 cal (30.0 ×4184 = 125520 J)
Temperature increases = 1.9°C
Specific heat of ring = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
125520 J = 0.012 g×c ×1.9°C
125520 J = 0.0228 g.°C ×c
c = 125520 J / 0.0228 g.°C
c = 5505263.16 J/g.°C
Answer:
Cold Front. A side view of a cold front (A, top) and how it is represented on a weather map (B, bottom). ...
Warm Front. ...
Stationary Front. ...
Occluded Front.
Answer:
Vaporization
Since the question does not specify what molecule is being acted upon by the increment in temperature, I'll assume it's water.
When first taken out of the fridge, water is in the form of ice, and it has not been affected by a change in temperature yet, so it's at the origin.
(origin = ice)
As you raise the temperature, however, the ice starts to melt, and melting occur during phase 2. You have to keep the temperature constant for the process to properly occur.
(phase 2 = melting)
After it finishes melting, the ice is now in it's liquid state, which is water. The temperature continues to rise in order to proceed to the next phase.
(2nd slope = water)
Lastly, Water is being vaporized during phase 4. Notice, the temperature is kept constant in order to allow the process to properly occur.
(phase 4 = vaporization)
M(KBr)=119.0 g/mol
v=625 mL=0.625 L
c=0.520 mol/L
n(KBr)=cv
m(KBr)=n(KBr)M(KBr)
m(KBr)=cvM(KBr)
m(KBr)=0.520*0.625*119.0=38.675 g
38.675 g
Answer:
the density of lithium will be equal to: 0.582 g/cm^3
Explanation:
We have the following data:
a = 430 pm = 4.3x10^-8 cm
molar mass of lithium MM = 6.97 g/mol
Since the cubic cell of lithium is cubic centered in the face, its value of Z will be equal to 4
Avogadro´s number AN = 6.022x10^23 particles/mol
using the following formula we will calculate the density of lithium:
d = (Z*MM)/(a^3*AN) = (4*6.97)/((4.3x10^-8)^3*(6.022x10^23)) = 0.582 g/cm^3