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balu736 [363]
3 years ago
10

Provide definitions for the following terms: a. Complex ion b. Complex c. Ligand d. Monodentate ligand e. Bidentate ligand f. Co

ordination number g. Calorimeter h. System (in this experiment) i. Surroundings in this experiment)
Chemistry
1 answer:
velikii [3]3 years ago
3 0

Explanation:

Complex ion:

Complex ion is a coordinate compound with metal ion in its centre bonded to two or more ligand by coordinate bond. Transition metals ions are present in the centre.

Complex:

Transition metals bonded to two or more ligand by coordinate bond or dative bond are called metal complex or complex.

Monodentate ligand:

In metal complexes, ions or molecules bonded to central metal or metal ion through coordinate bond are called ligand.

Ligands bonded to central metal through only one atom are called monodentate legand.

Binodentate ligand:

Ligands bonded to central metal through only two atoms are called bidentate legand.

Coordination number:

In a coordination compound, the no. of atoms bonded to cental atom or central metal ion is known as coordination number.

Calorimeter:

Calorimeters are used for the determination of amount of heat released or absorbed in a chemical reaction.

System:

In thermodynamics, fixed quantity of matter around which a boundary can be drawn is called a system.

Surrounding:

Surroundings is a boundary around a system through which mass and energy are transferred.

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2, stronger hydrogen bonding

Explanation:

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Theoretical yield: 35.0g<br> Actual yield: 27.7g<br> What is the percent yield?
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Answer:

Percentage yield=79.14%

Explanation:

Percentage yield=(Actual yield/theoretical yield)*100

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2 years ago
A 1.0857 gram pure sample of a compound containing only carbon, hydrogen, and oxygen was burned in excess oxygen gas. 2.190 g of
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Answer:

  • C₂ H₄ O

Explanation:

<u>1) Mass of carbon (C) in 2.190 g of carbon dioxide (CO₂)</u>

  • atomic mass of C: 12.0107 g/mol
  • molar mass of CO₂: 44.01 g/mol
  • Set a proportion: 12.0107 g of C / 44.01 g of CO₂ = x / 2.190 g of CO₂
  • Solve for x:

         x = (12.0107 g of C / 44.01 g of CO₂ ) × 2.190 g of CO₂ = 0.59767 g of C

<u />

<u>2) Mass of hydrogen (H) in 0.930 g of water (H₂O)</u>

  • atomic mass of H: 1.00784 g/mol
  • molar mass of H₂O: 18.01528 g/mol
  • proportion: 2 × 1.00784 g of H / 18.01528 g of H₂O = x / 0.930 g of H₂O
  • Solve for x:

        x = ( 2 × 1.00784 g of H / 18.01528 g of H₂O) × 0.930 g of H₂O = 0.10406 g of H

<u>3) Mass of oxygen (O) in 1.0857 g of pure sample</u>

  • Mass of O = mass of pure sample - mass of C - mass of H
  • Mass of O = 1.0857 g - 0.59767 g - 0.10406 = 0.38397 g O

Round to four decimals: Mass of O = 0.3840 g

<u>4) Mole calculations</u>

Divide the mass in grams of each element by its atomic mass:

  • C: 0.59767 g / 12.0107 g/mol = 0.04976 mol
  • H: 0.10406 g / 1.00784 g/mol = 0.10325 mol
  • O: 0.3840 g / 15.999 g/mol = 0.02400 mol

<u>5) Divide every amount by the smallest value (to find the mole ratios)</u>

  • C: 0.04976 mol / 0.02400 mol = 2.07 ≈ 2
  • H: 0.10325 mol / 0.02400 mol = 4.3 ≈ 4
  • O: 0.02400 mol / 0.02400 mol = 1

Thus the mole ratio is 2 : 4 : 1, and the empirical formula is:

  • <u>C₂ H₄ O </u>← answer
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