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Anettt [7]
3 years ago
5

What do potatoes, wood, and lobster shells have in common?

Chemistry
1 answer:
STatiana [176]3 years ago
5 0
They are all biotic factors, meaning they were once alive or were alive. (an abiotic factor is something that has never lived.) hope this helped.
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  What is the name of this hydrocarbon?
UkoKoshka [18]
Hydrocarbon tells you that it is a <span>six carbon compound containing a triple bond.</span>
8 0
3 years ago
Read 2 more answers
What element does the following orbital notation represent?
Snezhnost [94]
Answer is Ti

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5 0
4 years ago
If a pork roast must absorb kJ to fully cook, and if only 10% of the heat produced by the barbecue is actually absorbed by the r
kolezko [41]

Answer:

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

Explanation:

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g),\Delta H_{rxn}=-2044 kJ/mol (assuming)

Energy absorbed by pork,E = 1.6\times 10^3 kJ (assuming)

Total energy produced by barbecue = Q

Percentage of energy absorbed by pork = 10%

10\%=\frac{E}{Q}\times 100

Q=\frac{E}{10}\times 100=\frac{1.6\times 10^3 kJ}{10}\times 100=1.6\times 10^4 kJ

Since, it is a energy produced in order to indicate the direction of heat produced we will use negative sign.

Q = -1.6\times 10^4 kJ

Moles of propane burnt to produce Q energy =n

n\times \Delta H_{rxn}=Q

n=\frac{Q}{\Delta H_{rxn}}=\frac{-1.6\times 10^4 kJ}{-2044 kJ/mol}=7.83 mol

According to reaction , 1 mol of propane gives 3 moles of carbon dioxide. then 7.83 moles of will give:

\frac{1}{3}\times 7.83 mol=23.49 mol carbon dioxide gas.

Mass of 23.49 moles of carbon dioxide gas:

23.49 mol × 44 g/mol =1,033.56 g

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

8 0
3 years ago
What salt would form when each of the following
eduard
A.KCl
b.RbNO3
c.NaCl
d.CsBr
4 0
4 years ago
What is the specific heat capacity of silver metal if 55.00 g of the metal absorbs 193.9J of heat and the temperature rises 15.0
skad [1K]

Answer:

The specific heat capacity of silver is 0.24 j/g.°C.

Explanation:

Given data:

Mass of sample = 55.00 g

increase of temperature ΔT= 15.0 °C

Heat absorbed = 193.9 J

Specific heat capacity of silver = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance.

ΔT = change in temperature

Now we will put the values in formula.

193.9 J = 55.00 g × c ×15.0 °C

193.9 J = 825 g.°C  × c

c = 193.9 J / 825  g.°C

c= 0.24 /g.°C

The specific heat capacity of silver is 0.24 j/g.°C.

5 0
3 years ago
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