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3 years ago

Which angles are corresponding angles?

Mathematics

2 answers:

Zolol [24]3 years ago

8 0

Its ONL and PQS
theyre congruent

Firdavs [7]3 years ago

5 0

Pretty sure it is onl and pqs
sorry if i am wrong

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33. How will you check if your solution is correct?

Vsevolod [243]

Answer:

you basically do the same things just backwards

Step-by-step explanation:

for example 9+9=18 well to double check your work all you do is flip to equation 18-9=9

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2 years ago

15 points+brainliest!! please help asap, this is due tonight please!!

Masteriza [31]

Answer:

$x=\sqrt{13}$

Step-by-step explanation:

Base of the isosceles triangle = 4

Perpendicular of the triangle = 3

In an isosceles triangle , a perpendicular bisects a base equally. So, here the isosceles triangle consist of 2 right angled triangles.

In that right angled triangles,

Base = 4/2 = 2 (∵ A perpendicular divides a base into 2 equal parts. )

Perpendicular = 3

Hypotenuse = x

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3 years ago

A race car is equipped with a computer that records the reading on its speedometer every second during a race. if you graph this

Eva8 [605]

D.) Dependent variable is "<span>instantaneous velocity" as it gives information of velocity at every second

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3 0

3 years ago

Read 2 more answers

Can you solve this? It is for MATH 111

umka2103 [35]

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3 years ago

An observer (O) spots a plane flying at a 42° angle to his horizontal line of sight. If the plane is flying at an altitude of 15

NeTakaya

Answer:

D. 22,417 feet

Step-by-step explanation:

Fine the diagram in the attachment for proper elucidation. Using the SOH, CAH, TOA trigonometry identity to solve for the distance (x) from the plane (P) to the observer (O), the longest side x is the hypotenuse and the side facing the angle of elevation is the opposite.

Hypotenuse = x and Opposite = 15,000feet

According to SOH;

$sin 42^0 = \frac{Opposite}{Hypotenuse} \\\\Sin42^0 = \frac{15000}{x}\\ \\x = \frac{15000}{sin42^0}\\\\ \\$

$x = \frac{15000}{ 0.6691} \\\\x = 22,417 feet$

Hence the distance (x) from the plane P to the observer O is approximately 22,417 feet

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3 years ago