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Aleks04 [339]
3 years ago
5

Please help me‼️‼️‼️

Mathematics
1 answer:
rewona [7]3 years ago
6 0

Answer:

y= 4x-7

Step-by-step explanation:

First, we need to find the slope. We can do this by using the formula:

1) y₂-y₁/x₂-x₁

2) 9-5/5-3

3) 4/2

4) The slope is 2

Next, we have to first plug the slope (2) and one of the coordinate pairs (I chose (3,5)) into point-slope format.

5) y-y₁=m(x-x₁)

6) y-5 =4(x-3)

7) Now we just simplify this equation to make it slope intercept form (y=mx+b)

8) y-5= 4x-12

9) y=4x-7

And there you have it :)

You might be interested in
(1.2 x 10^13) - (4 x 10^11)
Alexandra [31]

Answer:

the answer is 11,600,000,000,000

Step-by-step explanation:

pemdas

(1.2 x 10 ^13) - (4 x 10 ^11)

10^13 = 10,000,000,000,000 put that in scientific notation to make it simpler do same for 10 ^11

10 x 10^13

(1.2 x 10 x 10^13) - ( 4 x 10 x 10^11)

now solve the first equasion

12,000,000,000,000 - 400,000,000,000

subtract

11,600,000,000,000

3 0
3 years ago
Please help me with this
zhuklara [117]

Answer:

301.6 ft³

Step-by-step explanation:

The volume (V) of a cone is calculated using the formula

V = \frac{1}{3} × area of base × perpendicular height (h)

h can be calculated by using Pythagoras' identity in the right triangle

with hypotenuse = 10 and legs 6 and h, thus

h² + 6² = 10²

h² + 36 = 100 ( subtract 36 from both sides )

h² = 64 ( take the square root of both sides )

h = \sqrt{64} = 8

Hence

V = \frac{1}{3} × π × 6² × 8

   = \frac{1}{3} × 288π = \frac{288\pi }{3} ≈ 301.6

7 0
3 years ago
What is 3.75 written in word form
lord [1]

Three and seventy-five hundredths.

Hope I helped! :P

7 0
4 years ago
Read 2 more answers
Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0. A. 3 B. 2
Zepler [3.9K]

Answer:

C. 0

Step-by-step explanation:

–4j^2 + 3j – 28 = 0

The discriminant is b^2-4ac  if >0 we have 2 real solutions

                                                   =0  we have 1 real solutions

                                                   <0 we have 2 imaginary solutions

a = -4, b =3  c = -28

b^2 -4ac

(3)^2 - 4(-4)*(-28)

9 - 16(28)

9 -448

This will be negative so we have two imaginary solutions.

Therefore we have 0 real solutions

5 0
4 years ago
Subtract 3x^2+8x3x <br> 2<br> +8x from -9x^2+3x-8−9x <br> 2<br> +3x−8
r-ruslan [8.4K]

Answer:

oogla boogla

Step-by-step explanation:

5 0
4 years ago
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