Question

Two twins are running away from their mother in opposite directions one with the speed of 10 feet per second and the other with the speed of 8 feet per second. How and with what speed does the distance between the twins change?

Answer 1

with speed of 18 feet per second the distance between the twins change.

Step-by-step explanation:

Here we have , Two twins are running away from their mother in opposite directions one with the speed of 10 feet per second and the other with the speed of 8 feet per second. We need to find How and with what speed does the distance between the twins change. Let's find out:

Two twins are running in opposite directions , Let us suppose one twin speed is denoted by $v_1$ , i.e. 10 feet per second

⇒ $v_1=10$

Now , Speed of other twin is $v_2$ , i.e. -8 feet per second . Minus sign shows the direction as this twin is moving in opposite direction :

⇒ $v_2=-8$

Now, Difference in both speeds will give the change in speed between them :

⇒ $v_1-v_2=10-(-8)$

⇒ $v_1-v_2=18$

Therefore , with speed of 18 feet per second the distance between the twins change.