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stellarik [79]
3 years ago
9

A new tire that you need for your bike has a radius of 13 inches. What is the circumference of the tire? Use 3.14 to approximate

pi. Round your answer to the nearest tenth.
Mathematics
1 answer:
suter [353]3 years ago
8 0
Circumference of a circle = 2π r 
2*3.14*13 = 81.64 = 81.6
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That's how i was taught back in the 4th grade... i'm not sure if it's correct but i hope it is-

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For each pair of similar figures, find the ratio of the area of the first figure to the area of the second.
Hitman42 [59]

answer:

\frac{4}{9}


explanation:

the area of the larger square is 36 (6*6), and the area of the smaller square is 16 (4*4). to find the ratio of the area, simply just put 16 over 36 and simplify.

\frac{16}{36} = \frac{4}{9}

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if this helped, please consider giving brainliest !

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3 years ago
Describe the end behavior of the given function f(x)=2/3x-2
Ipatiy [6.2K]

Answer:

The end behavior of f(x)=2/3x-2 is: as x->+ infinity, f(x)->+ infinity

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Step-by-step explanation:

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4 0
3 years ago
How do I solve 12 + 2x + 1 = 59
aksik [14]
You can look up cymath.com it will work the problem out for you and show you the steps.
3 0
3 years ago
Read 2 more answers
In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad
weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

\angle acd = 60 ^{\circ}

Therefore, we have

\angle dcb =90- 60= 30 ^{\circ}

Now, in triangle bcd, we have

\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
cd=5\sqrt 3

Now, in triangle acb, we have

tan 60 = \frac{ad}{5\sqrt3} \\
\\
\sqrt 3=  \frac{ad}{5\sqrt3}\\
\\
ad= 5\sqrt3 \times \sqrt 3\\
\\
ad= 5\times 3\\
\\
ad=15

Thus, ad is 15 cm.


4 0
3 years ago
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