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3 years ago

Given: circle k(O)

Mathematics

1 answer:

GaryK [48]3 years ago

5 0

Answer:

measure angle FP is 62°

Step-by-step explanation:

The angle R inscribes the arc FQ, so using the property of inscribed angles in a circle, we have that:

m∠R = mFQ / 2

The arc FQ is the sum of the arcs FP and PQ, so we have:

mFQ = mFP + mPQ = 11x + 7 + 60 = 11x + 67

Now, with the first equation, we have:

$12x + 1 = (11x + 67) / 2\\\\24x + 2 = 11x + 67\\\\13x = 65\\\\x = 5^\circ$

So we have that mFP

$= 11x + 7 \\\\= 55 + 7 \\\\= 62^\circ$

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What’s Distribute -x(5x+2)

MaRussiya [10]

Answer:

-5x^2-2x

Step-by-step explanation:

When distributing, you multiply the term outside the brackets to all the terms in brackets.

If the term outside the bracket is negative, then when distributing/opening the brackets, the signs of the terms changes.

So in this prob. -x would multiply to both +5x and +2

-x*5x+-x*2

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4 years ago

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What is the correct domain and range in set notation

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Answer:

The one on the middle left.

Explanation:

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3 years ago

Triangle FEG is similar to triangle IHJ. Find angle H.

Marysya12 [62]

i’m just as stupid man i need help on the exact same one

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3 years ago

If f(x)=x - 1 and g(x) = 5x – 2, then (f.g) (x)=

Serjik [45]

Answer:

Step-by-step explanation:

Hello,

If you mean

$(f.g)(x)=f(x).g(x)=(x-1)(5x-2)=5x^2-7x+2$

If you mean

$(fog)(x)=f(g(x))=(5x-2)-1=5x-3$

Thanks

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4 years ago

Sergeeva-Olga [200]

Answer: 114.37 ft

Step-by-step explanation:

If we model this situation as a right triangle, where the hypotenuse is the length of the ladder ( $110 ft$ ), the opposite leg is the height the ladder will reach $h$ , and the adjacent leg is the distance between the base of the ladder and the building ( $28 ft$ ); we have two options:

1) Using trigonometric functions, since we are given the angle $\theta=75\°$

2) Using the Pithagorean Theorem

Any of the options will give a similiar result. So, let's choose the Pithagorean Theorem:

$(hypotenuse)^{2}=(opposite-leg)^{2}+(adjacent-leg)^{2}$

$(110 ft)^{2}=(h)^{2}+(28 ft)^{2}$

Isolating $h$ :

$h=\sqrt{(110 ft)^{2}-(28 ft)^{2}}$

$h=106.37 ft$

Adding to this height the extra height of $8 ft$ (since the base of the ladder is at this distance above the ground, perhaps held by a firefighter truck):

$h=106.37 ft+8 ft=114.37 ft$ This is the height the ladder will reach

6 0

3 years ago