Answer:
28/3
Step-by-step explanation:
2 1/3 divided by 1/4
We’ll start by 2 1/3
Multiply 3 x 2 and then add 1
3 x 2 = 6 + 1 = 7
Then add the denominator back
7/3
Now divide 7/3 by 1/4 like this!
Start by multiplying 4 by 7
4 x 7 = 28
Then multiply 3 by 1
3 x 1 = 3
Final results: 28/3
Answer:
R: (16, 2)
Step-by-step explanation:
Let (x, y) be the point R
(x - 10)/2 = 3 and (y + 12)/2 = 7
x - 10 = 6 y + 12 = 14
x = 16 y = 2
R: (16, 2)
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
