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vitfil [10]
3 years ago
8

Determine if the statement is always, sometimes or never true.

Mathematics
1 answer:
mojhsa [17]3 years ago
3 0

Answer:

I think its c

Step-by-step explanation:

I'm pretty sure you need decimals to make it an irrational number

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Can you guys help me out pls
Slav-nsk [51]
It leaves Chicago at 11:49 am and takes 2 hrs 26 min.
So in central time, that gets you to Denver at 2:15 PM.
Since mountain time is one hour behind central time, your answer would be 1:15 PM.
5 0
3 years ago
The pictures is where my question is someone please answer it.
Naddik [55]

Answer:

functions: first one, third one, fifth one, seventh one, eigth one

the rest are not function

Step-by-step explanation:

if it is a function it either passes the line test or it doesnt have two outputs

8 0
2 years ago
What is the greatest common factor of 60 and 75? A.3 B.6 C.15 D.25
bekas [8.4K]
The answer is C, 15.
7 0
3 years ago
The graph below shows the solution set of which inequality?
svp [43]

Answer:

D x^2 smaller than or equal 4

Step-by-step explanation:

if you tried to get a number on the number line and put it to fit in the equation it will just end to equal or smaller than 4

6 0
3 years ago
Find domain of y=rad20-6x
Evgesh-ka [11]
Domain, on an "even root" context, means, an even root cannot have a negative radicand, since  say for example \bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x

now, if "x" is 10/3, let's see \bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example  \bf x=\frac{11}{3}
\\\\\\

\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish
5 0
3 years ago
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