Answer:
3y / (y+3)
Step-by-step explanation:
3y^2 - 6y / y^2 + y - 6
= 3y(y-2) / (y+3)(y-2)
=3y / (y+3)
The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
Learn more about spring constant:
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Answer:
Option C √32 is correct
Step-by-step explanation:
Here,
x₁ = 8
x₂ = 4
y₁ = (-3)
y₂ = (-7)
Now,
By Using Distance Formula
<em>D = √(x₂ - x₁)² + (y₂ - y₁)²</em>
<em> </em><em> </em><em> </em><em> </em>= √(4 - 8)² + [(-7) - (-3)]²
= √(-4)² + [(-7) + 3]²
= √16 + (-4)²
= √16 + 16
<u>D = √32</u>
Thus, The distance between (8, -3) and (4, -7) is √32
<u>-TheUnknown</u><u>S</u><u>cientist</u>
Answer:
$84.58
Step-by-step explanation:
You would do 9.95 times 8.5 which gives you 84.575 which in money case you round to two decimal places you keep the 5 but 7 you round to 8 because "5 or more you add one more"
Hope this helps
Dear Sweet21574, the answer is D. Squre pyramid.