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sp2606 [1]
3 years ago
13

Mason and Nora decided to swim across the river. Mason began swimming 7.7 seconds earlier than Nora. Mason swam at a speed of 5

feet per second. Nora swam at a speed of 5+1 feet per second. For how many seconds had Mason been swimming at the moment when the two swimmers had swam exactly the same distance?
Mathematics
1 answer:
user100 [1]3 years ago
7 0
Let d be distance travelled when they are level , and t = time that nora took to get level with mason for Nora 6 = d/t d = 6t for Mason 5 = d / (t + 35) d = 5 ( t + 350 so 6t = 5(t + 35) solve for t
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