Question

Mason and Nora decided to swim across the river. Mason began swimming 7.7 seconds earlier than Nora. Mason swam at a speed of 5 feet per second. Nora swam at a speed of 5+1 feet per second. For how many seconds had Mason been swimming at the moment when the two swimmers had swam exactly the same distance?

Answer 1

Let d be distance travelled when they are level , and t = time that nora took to get level with mason for Nora 6 = d/t d = 6t for Mason 5 = d / (t + 35) d = 5 ( t + 350 so 6t = 5(t + 35) solve for t