2 years ago

Find the distance between the points (2,4) and (6,1).

1 answer:

4 0

Answer:

Step-by-step explanation:2 and 6 are the first ones in each set so 6-2 is 4.4 and 1 are the second ones in each set 1-4 is -3 4+-3 is 1.

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The four points (−2, 5), (−2, −1), (6, −1), and (3, 5) are the vertices of a polygon. What is the area, in square units, of this

crimeas [40]

Look at the picture.

The polygon is a right-angled trapezoid.

The area is:
$A=\frac{a+b}{2} \times h$

The points (-2,-1) and (6,-1) lie on the same horizontal line, so the distance between them is 6-(-2)=6+2=8. The length of a is 8 units.
The points (-2,5) and (3,5) lie on the same horizontal line, so the distance between them is 3-(-2)=3+2=5. The length of b is 5 units.
The points (-2,5) and (-2,-1) lie on the same vertical line, so the distance between them is 5-(-1)=5+1=6. The length of h is 6 units.

$A=\frac{8+5}{2} \times 6=\frac{13}{2} \times 6=13 \times 3=39$

The area is 39 square units.