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mihalych1998 [28]

3 years ago

10

Find the distance between the points (2,4) and (6,1).

1 answer:

balu736 [363]3 years ago

4 0

Answer:

1

Step-by-step explanation:2 and 6 are the first ones in each set so 6-2 is 4.4 and 1 are the second ones in each set 1-4 is -3 4+-3 is 1.

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Please help quickly for 5 stars and brainliest!!

alexandr402 [8]

1.
Height h = 240 feet
We insert it into formula.
$240 = -16 t^{2} +128t$
Now we solve this for t:
$16 t^{2} -128t +240 = 0 /16 \\ t^{2} - 8t +15 =0 \\ t_{1} = 5 t_{2} = 3$

We have two answers as the rocket will pass this height on it's way up and down.

2.
Height h = 0 feet
We insert it into formula.
$0=-16 t^{2} +76t + 2$
Now we solve this for t:
$16 t^{2} - 76t -2 = 0 /2 \\ 8t^{2} - 38t - 1 = 0 \\ t_{1} = 5 t_{2} = -1$
We do not consider solution -1 as the time can not be negative. Our solution is 5s.

3.
Height at bottom of hill h = 0 feet
We insert it into formula.
$v^{2} = 64 * 0 = 0 ft/s$

7 0

4 years ago

Use the parabola tool to graph the quadratic function f(x) = x2 – 12x + 27.

Dennis_Churaev [7]

Answer:

7

Step-by-step explanation:

you would chose 7 because it has more and less value

5 0

3 years ago

Harry buys a waffle maker priced at $48. If the sales tax is 9%, how much tax will Harry pay?

Klio2033 [76]

Answer:

2325

Step-by-step explanation:

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8 0

3 years ago

. Joanne does a daily walk from building P to building Q. Given point P(6,9) and point Q(5,-4), what is the distance between poi

kotykmax [81]

Answer:

The distance between points P and Q on this campus map of the local college is 13.038 units

Step-by-step explanation:

We are given that Joanne does a daily walk from building P to building Q

$P=(x_1,y_1)=(6,9)\\Q = (x_2,y_2)=(5,-4)$

We are supposed to find the distance between points P and Q on this campus map of the local college

We will use distance formula :

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values in the formula .

$d=\sqrt{(5-6)^2+(-4-9)^2}\\d=13.038$

Hence the distance between points P and Q on this campus map of the local college is 13.038 units

5 0

4 years ago

The senior classes at High School A and High School B planned separate trips to the indoor

Mazyrski [523]

Answer:

The number of students in each <u>van are 7</u> and number of students in each <u>bus are 23.</u>

Step-by-step explanation:

Let the number of students in each van be 'x' and number of students in each bus be 'y'.

Given:

<u>High School A:</u>

Number of students = 132

Number of buses = 3

Number of vans = 9

As per question,

$9x+3y=132$ -------1

<u>High School B:</u>

Number of students = 205

Number of buses = 8

Number of vans = 3

As per question,

$3x+8y=205$ -------2

Multiplying equation (2) by -3 and adding the result to equation (1), we get:

$-3(3x+8y)=-3(205)\\-9x-24y=-615$

$-9x-24y=-615\\9x+3y=132\\---------\\-21y=-483\\y=\frac{-483}{-21}=23$

Now, plug in 23 for 'y' in equation (1) and solve for 'x'. This gives,

$9x+3(23)=132\\9x+69=132\\9x=132-69\\9x=63\\x=\frac{63}{9}=7$

Therefore, the number of students in each van are 7 and number of students in each bus are 23

7 0

3 years ago