The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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1. The coefficient of x is the constant of variation. It is 40.
2. -12 = -2*6 . . . . . you know this because you know your times tables
.. f(x) = -2x
Answer:
x=11 degrees
Step-by-step explanation:
45+4x+1=90
46+4x=90
4x=44
x=11
Answer:
Step-by-step explanation:
The first two steps are for the purpose of eliminating fractions. Doing so results in 4(2x - 5) = 9(x - 2), which is to be solved for x.
Perform the indicated multiplication, obtaining:
8x - 20 = 9x - 18.
Then combine like terms: -2 = x, or
x = -2.
To complete the formal check, substitute -2 for x in the first equation. This results in:
(1/3)(-4 - 5) = (3/4)(-2 -2), or
-3 = -3
... which is obviously true.
