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Measurement of "AC" :
(x + 5) + (2x <span>− 11) ;
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Find the measurement of "AB" [which is: "(x+5)" ]:
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First, simplify to find the measurement of "AC" :
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</span>(x + 5) + (2x − 11) ;
= (x + 5) + 1(2x − 11) ;
= x + 5 + 2x − 11 ;
→ Combine the "like terms" ;
x + 2x = 3x ;
5 − 11 = - 6 ;
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to get: 3x − 6 ;
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So, (x + 5) + (2x − 11) = 3x − 6 ;
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Solve for: "(x + 5)"
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We have:
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(x + 5) + (2x − 11) = 3x − 6 ;
Subtract: "(2x − 11)" ; from EACH SIDE of the equation ;
to isolate "(x + 5)" on one side of the equation;
and to solve for "(x + 5)" ;
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→ (x + 5) + (2x − 11) − (2x − 11) = (3x − 6) − (2x − 11) ;
→ (x + 5) = (3x − 6) − (2x − 11) ;
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Note: Simplify: "(3x − 6) − (2x − 11)" ;
→ (3x − 6) − (2x − 11) ;
= (3x − 6) − 1(2x − 11) ;
= 3x − 6 − 2x + 11 ;
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→ Combine the "like terms" :
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+3x − 2x = 1x = x ;
-6 + 11 = 5 ;
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To get: x + 5 ;
So we have:
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x + 5 = x + 5 ;
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So, x = all real numbers.
x = <span>ℝ </span>
They are up and down and left and right
False the +2 shifted to equation up 2 spots not left 2 spots
:)))
Answer: b) rolled three times, number of 2s rolled
d) rolled twice, number of odds rolled
<u>Step-by-step explanation:</u>
A binomial experiment must meet the following criteria:
- There must be a fixed number of trials (rolls)
- Each trial (roll) is independent of the others
- There are only two outcomes (success or fail)
- The probability of each outcome remains constant from trial to trial
a) rolled twice --> satisfies #1 & #2 (n = 2)
X is the sum --> fails #3 (more than two outcomes)
b) rolled three times --> satisfies #1 & #2 (n = 3)
X is the number of 2s rolled --> satisfies #3 & #4 (P success = 1/6)
c) rolled an unknown number of times - fails #1
d) rolled twice --> satisfies #1 & #2 (n = 2)
X is the number of odds rolled --> satisfies #3 & #4 (P success = 1/2)
Area:66 Perimeter:36
Step-by-step explanation:
Perimeter: 9+9+5+3+4+6: 36
as 9-5 is 3
and 9-3 is 6
Area: 9*6 +3*4: 66
