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Nuetrik [128]
3 years ago
6

Please help me! I'm spending 50 points on this question and my last two questions never even got answered!

Mathematics
1 answer:
Verdich [7]3 years ago
8 0

Answer:

C.

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

\frac{3x^2 + x^4 + 2}{4x - 3}

4x - 3 makes up our denominator, the bottom part of the fraction. So

4x - 3 = 0

4x = 3

x = 3/4

So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

\frac{x^2 - 4}{x-2}

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

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What undefined term defines an parellel line
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Parallel lines- lines that can go on and on without touching each other.
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4 years ago
Select the correct answer from the drop-down menu.
ELEN [110]

Missing term = –2xy

Solution:

Let us first find the quotient of -8x^2y^3 \div xy.

-8x^2y^3 \div xy=\frac{-8x^2y^3 }{xy}

                    =\frac{-8\times x\times x\times y\times y\times y}{xy}

Taking common term xy outside in the numerator.

                    =\frac{xy(-8\times x\times y\times y)}{xy}

Both xy in the numerator and denominator are cancelled.

                    =-8xy^2

Thus, the quotient of -8x^2y^3 \div xy is -8xy^2.

Given the quotient of -8x^2y^3 \div xy is same as the product  of 4xy and ____.

-8xy^2=4xy × missing term

Divide both sides by 4xy, we get

⇒ missing term = \frac{-8xy^2}{4xy}

Cancel the common terms in both numerator and denominator.

⇒ missing term = –2xy

Hence the missing term of the product is –2xy.

4 0
3 years ago
Find the mean and the MAD of the following data set. [Note: Type your answers as numbers. Do not round.] 10, 15, 20, 25, 30, 35
tiny-mole [99]

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3 0
3 years ago
Read 2 more answers
Solve x2 − 10x = −13.
aev [14]

Answer:

B

Step-by-step explanation:

First, let's rearrange the given equation into something more recognizable. If we add 13 to both sides, we now have the polynomial x^{2}-10x+13. We can now use the quadratic formula to solve.

Remember that the quadratic formula is

\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}

Substitute the numbers from the equation into the formula.

\frac{-(-10)+/-\sqrt{(-10)^{2}-4(1)(13) } }{2(1)}

Simplify:

\frac{10+/-\sqrt{100-52} }{2}

\frac{10+/-\sqrt{48} }{2}

Here, I'm going to assume that there was a mistype in option B because if we divide out the 2 we end up with 5+/-\sqrt{48}.

Hope this helps!

6 0
3 years ago
Tell whether −2 is a solution of the inequality. 8−2x<12
kolbaska11 [484]

Answer:

No

Step-by-step explanation:

8−2x<12

Subtract 2 from each side

8-8−2x<12-8

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Divide each side by -2, remembering to flip the inequality

-2x/-2 >4/-2

x > -2

Is -2 a solution

-2 >-2

This is false, it is equal

5 0
3 years ago
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