Answer:
a) 21.20 feet long b)51.20 feet of fencing
Step-by-step explanation:
a)
a²+b²=c²
15²+15²=c²
225+225=c²
450=c²
√450=c
21.213=c
21.20=c
b)
15+15+21.20= 51.20
Based on the given problem above, it requires a trigonometric solution. So here it goes:
The climb distance is:<span>200 * Sec <span>[<span>ArcTan <span>[10/200]</span></span>]</span> = 10</span>√ 401 km
and the decent distance is:<span>300 * Sec <span>[<span>ArcTan <span>[<span>10/300</span>]</span></span>]</span> = 10</span>√901 km
So add the given results above with 500 km and this will be the additional distance that <span>plane moves through the air.
The answer would be in the unit meters.
</span><span>(<span>(10</span></span>√401 +10√901−500)∗1000)=416 meters
Hope this is the answer that you are looking for.
The child is <u>59.4 inches tall</u>, assuming the length from the coach's shoulder to his head cap is approximately 10 inches.
<h3>What is Heigth?</h3>
Height refers to the vertical distance between the top and bottom of something.
Height measures the length of some objects or persons vertically to determine whether it is high or low, according to some ascertained criteria.
<h3>Data and Calculations:</h3>
Baseball coach's height = 70 inches
Coach's shoulder to head = 10.6 inches
Height of the child standing slightly below the coach's shoulder = 59.4 inches (70 - 10.6)
Thus, the child standing slightly below the coach's shoulder is 59.4 inches tall.
Learn more about height measurements at brainly.com/question/73194
#SPJ1
<h3>Question Completion:</h3>
Assume that the height of the coach from his shoulder to the head is 10.6 inches.
A = I * w
divide by w
I = A / w
Your answer is the third choice
Answer:
Step-by-step explanation:
(x-3)/2 = 9
x - 3 = 18
x = 21
(y-5)/2= 6
y - 5 = 12
y = 17
(21, 17)