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hram777 [196]
3 years ago
11

Create the setStyles() function using the commands listed in the steps below. Christine wants one of five fancy style sheets to

be randomly used when the page is opened. Declare the styleNum variable equal to the value returned by the randInt() function, using 5 as the parameter value.
Computers and Technology
1 answer:
jolli1 [7]3 years ago
3 0

Answer:

Hi there! This can be implemented in a simple Python function which uses the "random" module to generate the number.

Explanation:

Using Python as the languge, we can write a the below code in a file called styles.py. The first line imports the randint function from the "random" module. The setStyles() function declares an array or 5 elements (here I have just used numbers but these could be string names of the stylesheets as well). Next, styleNum is assigned the random number and the associated stylesheet is selected from the array of stylesheets.

styles.py

from random import randint

def setStyles():

   stylesheets = [1,2,3,4,5];

   styleNum = randint(1,5);

   stylesheet = stylesheets[styleNum];

   print(stylesheet);

setStyles();

You might be interested in
Create a new file that builds a shopping list from a user. There should be a input query that asks the user to list an item and
levacccp [35]

Answer:

Check the output

Explanation:

# -*- coding: utf-8 -*-

"""

Created on Thu Apr 12 00:39:11 2018

author:

"""

stocks ={

       "tomato soup": 20,

       "cheese": 8,

       "bread": 6,

       "milk": 8,

       "butter": 7,

       "coffee": 8,

       "ice cream": 5,

       "orange juice": 12,

       "bacon": 6,

       "tortilla chips": 14,

       "ramen": 24 }

prices ={

       "tomato soup": 1.85,

       "cheese": 3.99,

       "bread": 2.50,

       "milk": 3.59,

       "butter": 1.99,

       "coffee": 5.99,

       "ice cream": 2.99,

       "orange juice": 2.50,

       "bacon": 5.49,

       "tortilla chips": 3.00,

       "ramen": 0.99 }

def grocery_cost(item_list,quantity_list):

   totalcost = 0

   for i in range(len(item_list)):

       totalcost=totalcost+(quantity_list[i]*prices[item_list[i]])

       

   return totalcost

def stock(item):

   print("Number of itmes present in the stock:",stocks[item])

print("Welcome to the on-line grocery store!!")

print("Items that are available for purchase:")

for key in stocks.keys():

   print(key)

#chosen foods

print("Enter the item with quantity or Enter 'Q' when you are done")

item_list=[]

quantity_list=[]

while True:

   item=input('Enter the item name: ')

   if item=='Q' or item=='q':

       break

   item_list.append(item)

   while True:

       quan=int(input('Enter the number of item: '))

       if stocks[item] >=quan:

           quantity_list.append(quan)

           break

       else:

           stock(item)

           print('Your requirement is higher than stock available. Please enter again!!')

print("\nTotal cost:", "$",grocery_cost(item_list,quantity_list))

Kindly check the output in the attached image below.

7 0
3 years ago
from january 2005 through july 2015, approximately how many electronic data records in the United States were breached, exposing
Brums [2.3K]
From January 2005 through July 2017, approximately 853 million electronic data records in the US were breached.
This allowed the attackers to take control over people's personal data, such as their various credit card numbers, and other important data, as well as their addresses, etc. The cyber police, as well as the regular police have been working hard to stop this from happening, but the hackers are very strong and smart.
4 0
3 years ago
The most popular input device of a computer is a(n) ____.
zaharov [31]
A keyboard and a mouse

7 0
3 years ago
Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,
Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary                                        denary or decimal

11111111      =        2⁸      =             256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s =  /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11110000.000000                /20

now we have added 4 1s in the 3rd field to reserve 12 0s

<u><em>subnet mask: 255.255.</em></u><u><em>16.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1      </em></u><u><em> 1 </em></u><u><em>      1     1     1     1</em></u>

<u><em>128  64     32    </em></u><u><em>16</em></u><u><em>    8    4     2    1</em></u>

step 3

in the ip network address: 198.16.0.0/19 <em>(subnet representation)</em> we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

          Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts<u><em>+16: 198.16.</em></u><u><em>16</em></u><u><em>.0 - 198.16.31.255</em></u>

<u><em>                   +16: 198.16.</em></u><u><em>32</em></u><u><em>.0- 198.16.47.255 et</em></u>c

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11111000.000000                /21

now we have added 5 1s in the third field to reserve 11 0s

<u><em>subnet mask: 255.255.</em></u><u><em>8.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1       1       </em></u><u><em>1 </em></u><u><em>    1     1     1</em></u>

<u><em>128  64     32    16    </em></u><u><em>8 </em></u><u><em>   4     2    1</em></u>

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (<em>subnet representation</em>) we increment this using 8

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts <u><em>+16: 198.16.</em></u><u><em>24</em></u><u><em>.0- 198.16.31.255</em></u>

<em>                             </em><u><em> +16: 198.16.</em></u><u><em>32</em></u><u><em>.0- 198.16.112.255 et</em></u>c

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11110000.000000                /20

now we have added 4 1s in the 3rd field to reserve 12 0s

<u><em>subnet mask: 255.255.</em></u><u><em>16.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1       1       1     1     1     1</em></u>

<u><em>128  64     32    16    8    4     2    1</em></u>

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts <u><em>+16: 198.16.40.0- 198.16.55.255</em></u>

<em>                          </em><u><em>    +16: 198.16.56.0- 198.16.71.255 et</em></u>c

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11100000.000000                /19

now we have added 3 1s in the 3rd field to reserve 13 0s

<u><em>subnet mask: 255.255.</em></u><u><em>32.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1      </em></u><u><em> 1 </em></u><u><em>      1       1     1     1     1</em></u>

<u><em>128  64     </em></u><u><em>32  </em></u><u><em>  16    8    4     2    1</em></u>

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts <u><em>+16: 198.16.72.0- 198.16.103.255</em></u>

<em>                          </em><u><em>    +16: 198.16.104.0- 198.16.136.255 et</em></u>c

5 0
3 years ago
You must keep track of some data. Your options are: (1) A linked-list maintained in sorted order. (2) A linked-list of unsorted
ladessa [460]

Answer:

Question was incomplete and continued the question

For each of the following scenarios, which of these choices would be best? Explain your answer.

BST

Sorted Array

Un-sorted Array

a) The records are guaranteed to arrive already sorted from lowest to highest (i.e., whenever a record is inserted, its key value will always be greater than that of the last record inserted). A total of 1000 inserts will be interspersed with 1000 searches.

b) The records arrive with values having a uniform random distribution (so the BST is likely to be well balanced). 1,000,000 insertions are performed, followed by 10 searches.

Explanation:

Answer for a: Un-sorted array or Un-sorted linked list : as mentioned in the question itself that the records are arriving in the sorted order and search will not be O(log n) and insert will be not be O(n).

Answer for b : Un-sorted array or Un-sorted linkedlist : Number of the items to be inserted is already known which is 1,000,000 but it is very high and at the same time search is low. Unsorted array or Unsorted linked list will be best option here.

7 0
3 years ago
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