Answer:
there you go
Step-by-step explanation:
The length of a train car is 50.6 feet. This is 5.8 feet less than 6 times the width. What is the width?
l = 50.6
We are also given:
6w - 5.8 = 50.6
A=1/2x Base x Height
= 1/2 (10)(24)
=120
Answer:
15%
Step-by-step explanation:
hope i helped!! please follow ❤❤
Answer:
Option 1: CD is a perpendicular bisector of AB
Step-by-step explanation:
Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.
Formula to find slope
![m= \frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%20%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
Formula to Find Distance between two points
![D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28y_2-y_1%29%5E2%2B%28x_2-x_1%29%5E2%7D)
mAB ( represents , Slope of AB )
1. ![mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}](https://tex.z-dn.net/?f=mAC%3D%20%5Cfrac%7B3-2%7D%7B2-5%7D%3D%5Cfrac%7B1%7D%7B-3%7D%3D-%5Cfrac%7B1%7D%7B3%7D)
2. ![mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}](https://tex.z-dn.net/?f=mBC%3D%5Cfrac%7B2-1%7D%7B5-8%7D%3D%5Cfrac%7B1%7D%7B-3%7D%3D-%5Cfrac%7B1%7D%7B3%7D)
3. ![mCD=\frac{5-2}{6-5}=\frac{3}{1}=3](https://tex.z-dn.net/?f=mCD%3D%5Cfrac%7B5-2%7D%7B6-5%7D%3D%5Cfrac%7B3%7D%7B1%7D%3D3)
4. ![AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}](https://tex.z-dn.net/?f=AC%3D%5Csqrt%7B%283-2%29%5E2%2B%282-5%29%5E2%7D%20%3D%5Csqrt%7B%281%29%5E2%2B%28-3%29%5E2%7D%3D%5Csqrt%7B1%2B9%7D%3D%5Csqrt%7B10%7D)
5. ![BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}](https://tex.z-dn.net/?f=BC%3D%5Csqrt%7B%282-1%29%5E2%2B%285-8%29%5E2%7D%20%3D%5Csqrt%7B%281%29%5E2%2B%28-3%29%5E2%7D%3D%5Csqrt%7B1%2B9%7D%3D%5Csqrt%7B10%7D)
mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is ![-\frac{1}{3}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B3%7D)
![mAB=-\frac{1}{3}](https://tex.z-dn.net/?f=mAB%3D-%5Cfrac%7B1%7D%7B3%7D)
![mCD=3](https://tex.z-dn.net/?f=mCD%3D3)
![mAB \times mCD = -\frac{1}{3} \times 3 = -1](https://tex.z-dn.net/?f=mAB%20%5Ctimes%20mCD%20%3D%20-%5Cfrac%7B1%7D%7B3%7D%20%5Ctimes%203%20%3D%20-1)
Hence CD ⊥ AB
Also
From Point 4 and point 5 above , we see that
AC = CB
Hence CD bisect AB at C, also CD ⊥ AB
There fore
CD is a perpendicular bisector of AB
Therefor option 1 is true