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2 years ago

Prove the polynomial identity.

Mathematics

2 answers:

bazaltina [42]2 years ago

5 0

Answer:

Step-by-step explanation:

Ronch [10]2 years ago

3 0

Answer:

The answer to your question is: 2, 4, 5, 1 , 3

Step-by-step explanation:

The first line is the second

(3x² - 6)² - (3x²)² = 36(1 - x)(1 + 1)

The second line is the forth

9x⁴ - 36x² + 36x² - 9x⁴ = 36(1 - x)(1 + x)

The next line is the fifth

36 - 36x² = 36(1 - x)(1 + x)

The next line is the first

36(1 - x²) = 36(1 - x)(1 + x)

The last line is the third

36(1 - x)(1 + x) = 36(1 - x)(1 + x)

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2 years ago

Please help... I have no clue

muminat

Answer:

OPTION C: Sin C - Cos C = s - r

Step-by-step explanation:

ABC is a right angled triangle. ∠A = 90°, from the figure.

Therefore, BC = hypotenuse, say h

Now, we find the length of AB and AC.

We know that: $\textbf{Sin A} = \frac{\textbf{opp}}{\textbf{hyp}}$

and $\textbf{Cos A} = \frac{\textbf{adj}}{\textbf{hyp}}$

Given, Sin B = r and Cos B = s

⇒ $Sin B = r = \frac{opp}{hyp} = \frac{AC}{BC} = \frac{AC}{h}$

⇒ $\textbf{AC} = \textbf{rh}$

Hence, the length of the side AC = rh

Now, to compute the length of AB, we use Cos B.

$Cos B = s = \frac{adj}{hyp} = \frac{AB}{BC} = \frac{AB}{h}$

⇒ $\textbf{AB} = \textbf{sh}$

Hence, the length of the side AB = sh

Now, we are asked to compute Sin C - Cos C.

$Sin C = \frac{opp}{hyp}$

⇒ $Sin C = \frac{AB}{BC}$

$= \frac{sh}{h}$

= s

Sin C = s

$Cos C = \frac{adj}{hyp}$

$\implies Cos C = \frac{AC}{BC}$

⇒ Cos C = $\frac{rh}{h}$

Therefore, Cos C = r

So, Sin C - Cos C = s - r, which is OPTION C and is the right answer.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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