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2 years ago

lemont has 30 books to pack the boxes each box holds 7 books if he fills each box how many boxes are left over

Mathematics

1 answer:

mariarad [96]2 years ago

6 0

Answer:

2 books

Step-by-step explanation:

If 7 books= 1 box

Then 30 books= 30÷7= 4 boxes with a remainder of 2 books

Therefore books left over= 2 books

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Chapman’s brickyard sells bricks and blocks. A brick costs $0.38 and a block costs $1.56. The brickyard filled a $24.80 order, w

Lisa [10]

Answer:

number of bricks = 16 and number of blocks = 12

Step-by-step explanation:

From given information it seems , we need to determine number of bricks and number of blocks.

lets assume number of bricks = x

and number of blocks = y

since total items in brickyard is 28

⇒ number of bricks + number of blocks = 28

⇒ x + y = 28 ----------------------- equation 1

Given that cost of 1 brick = $0.38 and cost of 1 block =$1.56

so cost of x bricks = cost of 1 brick × x = 0.38x

And cost of y blocks = cost of 1 block × y = 1.56y

total cost of 28 items order = $24.80

total cost of 28 items = cost of x bricks + cost of y blocks

⇒0.38x + 1.56y = 24.80 ----------------equation 2

Now we are having following two equations

x + y = 28 ----------------------- equation 1

0.38x + 1.56y = 24.80 ----------------equation 2

from equation 1 we get x = 28 - y , substituting this value of x in equation 2 we get

0.38(28 - y) + 1.56y = 24.80

⇒10.64-0.38y+1.56y= 24.80

⇒1.18y = 24.80 - 10.64

⇒y = 14.16÷1.18 = 12

substituting value of y in equation 1 we get

x + 12 = 28

⇒x = 16

hence number of bricks = x = 16 and number of blocks = y = 12

4 0

3 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

5 0

3 years ago

What square root expression represents the golden ratio?

Juli2301 [7.4K]

I believe the phi ratio^2 = 1 + phi ratio
phi ratio = 1.6180339
phi ratio^2 = 2.6180339

4 0

3 years ago

(04.03) The graph shows the amount of money paid when purchasing bags of candy at the 2008

alexandr1967 [171]

Answer: yw

y=4.03x+2008

6 0

3 years ago

What is the simplified form of 3abc/abc, when abc does not equal zero? Explain using the properties of real numbers.

elixir [45]

3abc / abc
= 3 ( abc ) / abc
= 3

because the real numbers did not have zero. the real number are starting from positive 1 to positive infinity number.
If we suppose a = 1, b = 2, c = 3
abc / abc = 1.

I hope that i helped you :)

4 0

3 years ago

Read 2 more answers