The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
To learn more on quadratic functions: brainly.com/question/5975436
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(15 qt/hr) x (1/4 gal/qt) x (1/60 hr/min) =
(15) / (4 x 60) = 0.0625 gal/min
Answer:
Yes
Step-by-step explanation:
They are exact and you can't mess up or accidentally slide the compass or straightedge around. This is just my opinion though.
Answer: no tommyinnit is swag let him rock dude
Step-by-step explanation: cause i said so
Answer:
(a)
(b)5,832 Mosquitoes
(c)5 days
Step-by-step explanation:
(a)Given an original amount
at t=0. The population of the colony with a growth rate
, where k is a constant is given as:

(b)If
and the population after 1 day, N(1)=1800
Then, from our model:
N(1)=1800

Therefore, our model is:

In 3 days time

The population of mosquitoes in 3 days time will be approximately 5832.
(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.
From our model

In approximately 5 days, the population of mosquitoes will be 20,000.