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2 years ago

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The millage rate in an area is 12.43 mills. What is the amount of property tax for a $141,300 house? Enter your answer as a doll

ar value, such as: 3456.78

1 answer:

mihalych1998 [28]2 years ago

7 0

<u>Answer:</u>

Amount of property tax for a $141,300 house with millage rate in an area 12.43 mills is $1756.36.

<u>Step-by-step explanation:</u>

<u>A millage rate is the tax rate used to calculate local property taxes . It represents the amount per every $1,000 of a property's assessed value.</u>

We have, 12.43 mills (12.43/1000 ) as millage rate i.e. which means for every $1,000 assessed value, $12.43 in property taxes is due.

∴ Homeowner owes : <em>$141,300 × ( 12.43/1000 ) = </em><em>$1756.36 property tax</em>.

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damaskus [11]

Answer & Step-by-step explanation:

The formula is given in the middle. You are supposed to insert the value of x into this formula to find the value of y (like in the first given example):

$x=-2\\y=2(-2)+5\\y=-4+5\\y=1$

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$x=-1\\y=2(-1)+5\\y=-2+5\\y=3$

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$x=0\\y=2(0)+5\\y=0+5\\y=5$

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$x=1\\y=2(1)+5\\y=2+5\\y=7$

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$x=2\\y=2(2)+5\\y=4+5\\y=9$

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3 years ago

A production process fills containers by weight. Weights of containers are approximately normally distributed. Historically, the

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Answer:

option (c) n = 201

Step-by-step explanation:

Data provided in the question:

Standard deviation, s = 5.5 ounce

Confidence level = 99%

Length of confidence interval = 2 ounces

Therefore,

margin of error, E = (Length of confidence interval ) ÷ 2

= 2 ÷ 2

= 1 ounce

Now,

E = $\frac{zs}{\sqrt n}$

here,

z = 2.58 for 99% confidence interval

n = sample size

thus,

1 = $\frac{2.58\times5.5}{\sqrt n}$

or

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3 years ago

If the dimensions of a circle are tripled, the area of the resulting circle will also be three times larger.

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Answer:

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Step-by-step explanation:

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3 years ago

Joe has a 28 foot long board. He needs to cut it into 24 equal length part. H owmany feet long should each section of the board

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2 years ago

Read 2 more answers

Formulate the situation as a system of two linear equations in two variables. Be sure to state clearly the meaning of your x- an

slega [8]

Answer:

1) There were 33 $4,000 investors and 27 $8,000 investors.

2) The solution in x = 4, y = 9.

3) There were 24 nickels and 56 dimes.

Step-by-step explanation:

1) A lawyer has found 60 investors for a limited partnership to purchase an inner-city apartment building, with each contributing either $4,000 or $8,000. If the partnership raised $348,000, then how many investors contributed $4,000 and how many contributed $8,000?

I am going to say that:

x is the number of investors that contributed 4,000.

y is the number of investors that contributed 8,000.

Building the system:

There are 60 investors. So:

$x + y = 60$

In all, the partnership raised $348,000. So:

$4000x + 8000y = 348000$

I am going to simplify by 4000. So:

$x + 2y = 87$

Solving the system:

The elimination method is a method in which we can transform the system such that one variable can be canceled by addition. So:

$1)x + y = 60$

$2)x + 2y = 87$

I am going to multiply 1) by -1. So we have

$1)-x - y = -60$

$2)x + 2y = 87$

By addition, the x are going to cancel each other

$-x + x - y + 2y = -60 + 87$

$y = 27$

For x:

$x + y = 60$

$x = 60-y = 60-27 = 33$

There were 33 $4,000 investors and 27 $8,000 investors.

2) Solve the system by row-reducing the corresponding augmented matrix.

$2x + y = 17$

$x + y = 13$

This system has the following augmented matrix:

$\left[\begin{array}{ccc}2&1&17\\1&1&13\end{array}\right]$

To help the row reducing, i am going to swap the first with the second line:

$L1 L2$

So we have:

$\left[\begin{array}{ccc}1&1&13\\2&1&17\end{array}\right]$

Now, reducing the first column.

$L2 = L2 - 2L1$

So we have:

$\left[\begin{array}{ccc}1&1&13\\0&-1&-9\end{array}\right]$

Now we do:

$L2 = -L2$

And the matrix is:

$\left[\begin{array}{ccc}1&1&13\\0&1&9\end{array}\right]$

Now to reduce the second column, we do:

$L1 = L1 - L2$

$\left[\begin{array}{ccc}1&0&4\\0&1&9\end{array}\right]$ .

So the solution is:

x = 4, y = 9.

3) A jar contains 80 nickels and dimes worth $6.80. How many of each kind of coin are in the jar?

I am going to say that x is the number of nickels and y is the number of dimes.

Each nickel is worth 5 cents and each dime is worth 10 cents.

Building the system:

There are 80 coins in all:

$x + y = 80$

They are worth $6.80. So:

$0.05x + 0.10y = 6.80$

Solving the system:

$1)x + y = 80$

$2)0.05x + 0.10y = 6.80$

I am going to divide 1) by -10, so we can cancel y. So:

$1)-0.10x - 0.10y = -8$

$2)0.05x + 0.10y = 6.80$

Adding:

$-0.10x + 0.05x - 0.10y + 0.10y = -8 + 6.80$

$-0.05x = -1.2$ *(-100)

$5x = 120$

$x = \frac{120}{5}$

$x = 24$

Also

$x + y = 80$

$y = 80-x = 80-24 = 56$

There were 24 nickels and 56 dimes.

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3 years ago