A horizontal shift would be in the form <span><span>f(x±k)</span></span>
B subtract 18 from both sides
(a)
Domain:
we know that domain is all possible values of x for which any function ios defined
Here, curve is defined for all values of x
so, domain is

Range:
Range is all possible values of y for which x is defined
minimum value of y is -4
maximium value of y is +inf
so, range is

(b)
x-intercept:
It is the value of x where f(x)=0
so, the point where curve intersects on x-axis
and we get


and

(c)
Increasing interval:
where curve is moving upward
we can see that

Decreasing interval:
where curve is moving downward
we get

Constant:
constant means horizontal line
there is no horizontal line here
so, it does not exist
(D)
End behavior:
when x-->+inf
y is moving upward
so, y---->+inf
when x-->-inf
y is moving upward
so, y---->+inf
(E)
we can see that curve jupms at x=-1
so, there is discontinuity at x=-1
and this is jump type of discontinuity
(F)
For odd:
f(-x)=-f(x)
For even:
f(-x)=f(x)
we can see that none of them holds true
so, this is neither
Answer:
<h2>
The answer is A</h2><h2>A. S = 1/2p - L</h2>
Step-by-step explanation:
Step one:
given the perimeter function
P = 2S + 2L
we are expected in this problem to change the subject of the formula to S
Step two:
firstly, let us isolate the term that has S
2S=P-2L
divide both sides by 2
2S/2= (P-2L)/2
S=P/2-L
S = 1/2p - L